Last visit was: 03 May 2026, 23:57 It is currently 03 May 2026, 23:57
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
manhasnoname
Joined: 21 Apr 2016
Last visit: 03 Feb 2025
Posts: 138
Own Kudos:
Given Kudos: 79
Products:
Posts: 138
Kudos: 75
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 03 May 2026
Posts: 110,043
Own Kudos:
Given Kudos: 106,009
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 110,043
Kudos: 812,752
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
sreenu7464
Joined: 19 Mar 2015
Last visit: 04 Jan 2018
Posts: 12
Own Kudos:
Given Kudos: 1
Location: India
Posts: 12
Kudos: 8
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 03 May 2026
Posts: 110,043
Own Kudos:
812,752
 [1]
Given Kudos: 106,009
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 110,043
Kudos: 812,752
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
sreenu7464
Is the integer 2b divisible by 6 ?

(1) 8b is divisible by 3.

(2) 9b is divisible by 12

its clearly asked whether the Integer 2b is divisible by 6.....so we can only to take the values to b which satisfies 2b as integer even 3/2 is possible but not 3/4

from statement 1----> 8b =>4*2b when divisible by 3 the possible values from given and statement 1 combined are 3/2,3,6......
conclusion:- statement 1 is enough to solve the question

statement 2 is clearly not enough to solve the equation.

So my answer would be A

The answer is NOT A it's C. It's explained several times on previous pages:

For a NO answer in (1) consider b = 3/2 --> 8b = 12, so it's divisible by 3 but 2b = 3, so not divisible by 6.
For an YES answer in (1) consider b = 3 --> 8b = 24, so it's divisible by 3 and 2b = 6, so divisible by 6.
avatar
LinhTranvu
Joined: 10 Mar 2018
Last visit: 13 May 2018
Posts: 1
Posts: 1
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Option 1: 8b divisible for 3 ==> b divisible for 3 ==> From 1, do not have enough info for answer
Option 2: 9b divisible for 12 ==> b divisible for 2 ==> From 2, do not have enough info for answer

From 1 and 2==> b divisible for 6 => answer C

Please hit kudo if it helps! THanks.
User avatar
standyonda
Joined: 31 Aug 2016
Last visit: 22 Nov 2021
Posts: 34
Own Kudos:
Given Kudos: 11
Posts: 34
Kudos: 5
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
sreenu7464
Is the integer 2b divisible by 6 ?

(1) 8b is divisible by 3.

(2) 9b is divisible by 12

its clearly asked whether the Integer 2b is divisible by 6.....so we can only to take the values to b which satisfies 2b as integer even 3/2 is possible but not 3/4

from statement 1----> 8b =>4*2b when divisible by 3 the possible values from given and statement 1 combined are 3/2,3,6......
conclusion:- statement 1 is enough to solve the question

statement 2 is clearly not enough to solve the equation.

So my answer would be A

The answer is NOT A it's C. It's explained several times on previous pages:

For a NO answer in (1) consider b = 3/2 --> 8b = 12, so it's divisible by 3 but 2b = 3, so not divisible by 6.
For an YES answer in (1) consider b = 3 --> 8b = 24, so it's divisible by 3 and 2b = 6, so divisible by 6.

Is it ok to make it from 2b/6 to b/3? Do we lose anything?
User avatar
amanvermagmat
User avatar
Retired Moderator
Joined: 22 Aug 2013
Last visit: 28 Mar 2025
Posts: 1,142
Own Kudos:
Given Kudos: 480
Location: India
Posts: 1,142
Kudos: 2,980
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The answer is NOT A it's C. It's explained several times on previous pages:

For a NO answer in (1) consider b = 3/2 --> 8b = 12, so it's divisible by 3 but 2b = 3, so not divisible by 6.
For an YES answer in (1) consider b = 3 --> 8b = 24, so it's divisible by 3 and 2b = 6, so divisible by 6.[/quote]

Is it ok to make it from 2b/6 to b/3? Do we lose anything?[/quote]

Hello

You are correct. Asking 'whether 2b is divisible by 6' is same as asking 'whether b is divisible by 3'.
In any case wherever 2b is divisible by 6, b has to be divisible by 3.
User avatar
GMATStudyStudent
Joined: 27 Jun 2019
Last visit: 30 Apr 2024
Posts: 20
Own Kudos:
Given Kudos: 89
Location: India
GRE 1: Q165 V164
GRE 1: Q165 V164
Posts: 20
Kudos: 6
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Quote:
Is the integer 2b divisible by 6 ?

Quote:
(1) 8b is divisible by 3.

Thus, \(8b = 3k\), k is an integer
\(b=\frac{3}{8} k\)

But 2b is an integer,
Thus \(2b=\frac{3}{4} k\) is an integer

Thus, \(2b = 3k\)

Thus, \(b = \frac{3}{2} k\)

Not Sufficient

Quote:
(2) 9b is divisible by 12

Thus, \(9b = 12m\), m is an integer
\(b=\frac{4}{3} m\)

But 2b is an integer
Thus \(2b= \frac{8}{3}m\) is an integer

Thus \(2b = 8m\)

Thus \(b= 4m\)

Not Sufficient

Combining:

b is a multiple of \(\frac{3}{2} and \frac{4}{1}\)

LCM of \(\frac{3}{2} and \frac{4}{1} = \frac{LCM(3,4)}{HCF(2,1)} = 12\)

Thus b is a multiple of 12.

Sufficient
User avatar
AritraKundu
Joined: 05 Feb 2017
Last visit: 23 Jul 2023
Posts: 15
Own Kudos:
Given Kudos: 80
Posts: 15
Kudos: 9
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Concept: Any number is divisible by 6 if
1. the unit digit is even
2. The summation of the digits is divisible by 3
We only need to check if b is even and 2+b is divisible by 3

Statement 1: 8b is divisible by 3
81 (b=1) is divisible by 3
84 (b=4) is divisible by 3
87 (b=7) is divisible by 3
B can hold the value 1,4 and 7 but remember that we need to check if all of these are even or not. Here it has both even and odd, statement 1 is not sufficient

Statement 2: 9b is divisible by 12
means it is divisible by 2*2*3
So the number have to nullify the entire denominator if 2*2*3
3 cuts 9, so 3 goes off from denominator
Now only if b has 4 or 8 then it can nullify 2*2 in the denominator
That means b can be 4 or 8
Now test for whether 2+b is divisible by 3
2+4=6 divisible by 3
2+8=10 not divisible by 3
So, statement 2 is not sufficient

Now if you check for statement A and B together, then we know from statement 1 that
b=1,4,7
Statement 2 that b=4,8
Means b=4 is only the common value
So the number 2b is 24
I can now determine whether it is divisible by 6
Answer C
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 39,014
Own Kudos:
Posts: 39,014
Kudos: 1,122
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
   1   2 
Moderators:
Math Expert
110043 posts
498 posts
226 posts