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SunShine
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Is the product of two real numbers x and y > 20 (1) 06 Mar 2006, 17:59
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Is the product of two real numbers x and y > 20

(1) 68



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Is the product of two real numbers x and y > 20 (1) 06 Mar 2006, 18:12
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SunShine
Is the product of two real numbers x and y > 20

(1) 6<x<9
(2) 3y>8
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I) not enough, X is in the interval (6,9) and Y can be any real number so
no idea if X*Y > 0

II) no information about X, so not enough

both

from II if Y> 8/3 then the lowest bound of the product X*Y is

6*(8/3) = 24

since 24 > 20

I would go with C
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Is the product of two real numbers x and y > 20 (1) 06 Mar 2006, 19:26
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since y is unknown NOT SUFFICIENT
since x is unknown NOT SUFFICIENT

combining

we have 6<x<9 meaning x is between 6.0001 (for example) and 8.9999

and y = 8/3 which is 2.66667

if you take 6.0001 * 2.66667 is 16.0007 something
however 8.999 * 2.66667 is approximately 23.999

NOT SUFFICIENT

So the answer is E
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Is the product of two real numbers x and y > 20 (1) 06 Mar 2006, 20:40
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I choose C .
The question asks whether the product is greater than 20 or not and by combining both the options it can be said for sure whether it is lesser or greater than 20.
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Is the product of two real numbers x and y > 20 (1) 07 Mar 2006, 00:43
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I agree with gmat krishna. This has to be E since y being greater than 2.66666 could also be 2.67 which till gives a value 18.69 (7*2.67) which is less than 20.

so
7*2.67 = 18.69
7*3 = 21
We cant be sure.

8*2.67 = 21.36 (will always be greater than 20. (but we dont know whether x is 8 for sure.)

both sattements are together not sufficient.
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Is the product of two real numbers x and y > 20 (1) 07 Mar 2006, 07:19
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Consider the lowest value for x and y, then take the product:

From 1, x>6
From 2, 3y> 8 implies y > 8/3

xy > 6 * (8/3) = 48/3 = 16

xy > 16

There's not enough information to go on to tell whether xy is greater to or less than 20

I go with E)
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Is the product of two real numbers x and y > 20 (1) 07 Mar 2006, 07:30
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gmatkrishna
since y is unknown NOT SUFFICIENT
since x is unknown NOT SUFFICIENT

combining

we have 6<x<9 meaning x is between 6.0001 (for example) and 8.9999

and y = 8/3 which is 2.66667

if you take 6.0001 * 2.66667 is 16.0007 something
however 8.999 * 2.66667 is approximately 23.999

NOT SUFFICIENT

So the answer is E
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I choose E for the same reason that gmat Krishna has mentioned.
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Is the product of two real numbers x and y > 20 (1) 07 Mar 2006, 07:48
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stmt 1 -- insuff dont know anything abt x
stmt 2 -- insuff dont know anything about y

taking to together,

x=7, y = 2.7 xy = 19.9 <20
x=7, y =3 xy =21 > 20

Hence E
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Is the product of two real numbers x and y > 20 (1) 07 Mar 2006, 11:19
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E too. 7*8/3 < 20 and 7 *10/3 > 20
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Is the product of two real numbers x and y > 20 (1) 07 Mar 2006, 11:40
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conocieur


I) not enough, X is in the interval (6,9) and Y can be any real number so
no idea if X*Y > 0

II) no information about X, so not enough

both

from II if Y> 8/3 then the lowest bound of the product X*Y is

6*(8/3) = 24

since 24 > 20

I would go with C
Show more


The bold part need relook.
E with others.
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conocieur
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Is the product of two real numbers x and y > 20 (1) 07 Mar 2006, 12:48
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duttsit
conocieur


I) not enough, X is in the interval (6,9) and Y can be any real number so
no idea if X*Y > 0

II) no information about X, so not enough

both

from II if Y> 8/3 then the lowest bound of the product X*Y is

6*(8/3) = 24

since 24 > 20

I would go with C

The bold part need relook.
E with others.
Show more


Yep that is 16, :stupid2
so is E

and that is why i didn't break 700+
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Is the product of two real numbers x and y > 20 (1) 07 Mar 2006, 15:59
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The OA is E.

As some of you have explained.



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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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