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Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

(1) y > 3x (2) y > x > 3

when i am combining 2 stmnts i am getting C as the answer.how could that X minimum value is 4. (1+2) 3<x<y and 3x<y. so 3<3x<y. Is this correct

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

Given integers are: {3, 4, 5, 6, x, y}

(1) y > 3x --> if x=1 and y=4 then the range=6-1=6<9 but if x=100 then the range>9. Not sufficient.

(2) y > x > 3 --> if x=4 and y=5 then the range=6-3=3<9 but if x=100 then the range>9. Not sufficient.

(1)+(2) From x > 3 we have that the least value of x is 4, and from y > 3x=12 we have that the least value of y is 13, hence the least value of the range is 13-3=10>9. Sufficient.

Re: Is the range of the integers 6, 3, y, 4, 5, and x greater th [#permalink]

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01 Nov 2014, 16:39

1

This post received KUDOS

Bunuel wrote:

TomB wrote:

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

(1) y > 3x (2) y > x > 3

when i am combining 2 stmnts i am getting C as the answer.how could that X minimum value is 4. (1+2) 3<x<y and 3x<y. so 3<3x<y. Is this correct

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

Given integers are: {3, 4, 5, 6, x, y}

(1) y > 3x --> if x=1 and y=4 then the range=6-1=6<9 but if x=100 then the range>9. Not sufficient.

(2) y > x > 3 --> if x=4 and y=5 then the range=6-3=3<9 but if x=100 then the range>9. Not sufficient.

(1)+(2) From x > 3 we have that the least value of x is 4, and from y > 3x=12 we have that the least value of y is 13, hence the least value of the range is 13-3=10>9. Sufficient.

Answer: C.

Hey Bunuel,

In the question, we are talking about integers so why are we not considering negative values. Wouldn't the statements be insufficient in that case. Can you please explain why negative integers are out of scope

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

(1) y > 3x (2) y > x > 3

when i am combining 2 stmnts i am getting C as the answer.how could that X minimum value is 4. (1+2) 3<x<y and 3x<y. so 3<3x<y. Is this correct

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

Given integers are: {3, 4, 5, 6, x, y}

(1) y > 3x --> if x=1 and y=4 then the range=6-1=6<9 but if x=100 then the range>9. Not sufficient.

(2) y > x > 3 --> if x=4 and y=5 then the range=6-3=3<9 but if x=100 then the range>9. Not sufficient.

(1)+(2) From x > 3 we have that the least value of x is 4, and from y > 3x=12 we have that the least value of y is 13, hence the least value of the range is 13-3=10>9. Sufficient.

Answer: C.

Hey Bunuel,

In the question, we are talking about integers so why are we not considering negative values. Wouldn't the statements be insufficient in that case. Can you please explain why negative integers are out of scope

Second statement says that y > x > 3, so both x and y are positive.

Re: Is the range of the integers 6, 3, y, 4, 5, and x greater th [#permalink]

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16 Aug 2016, 20:11

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Re: Is the range of the integers 6, 3, y, 4, 5, and x greater th [#permalink]

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20 Aug 2016, 04:51

Hi Bunuel,

From x > 3 the minimal value of x is 4, and the min value of y is 13 as per y> 3x=12, So the range should br 13-4=9 Can you please explain why the value of the range is 10 .

Re: Is the range of the integers 6, 3, y, 4, 5, and x greater th [#permalink]

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20 Aug 2016, 05:25

AbhijitGoswami wrote:

Hi Bunuel,

From x > 3 the minimal value of x is 4, and the min value of y is 13 as per y> 3x=12, So the range should br 13-4=9 Can you please explain why the value of the range is 10 .

Thanks

It should be 13-4 = 9 only.

It MUST be a typo from Bunuel side.
_________________

Re: Is the range of the integers 6, 3, y, 4, 5, and x greater th [#permalink]

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24 Jul 2017, 21:08

Dear friends, If we read the question carefully it means that the range of the 6,3,y,4,5 and (of) x greater than 9. If we combine the 2 statements and take x=4 then y >12, say 13 then the range of the series is 13-3=10 and range of series and x = 10-4= 6 which is less than 9. if we take x=7, then y>21 say 22, then range of series is 22-3=19 and range of 19 and 7 is 12. so E should be the ans.

Dear friends, If we read the question carefully it means that the range of the 6,3,y,4,5 and (of) x greater than 9. If we combine the 2 statements and take x=4 then y >12, say 13 then the range of the series is 13-3=10 and range of series and x = 10-4= 6 which is less than 9. if we take x=7, then y>21 say 22, then range of series is 22-3=19 and range of 19 and 7 is 12. so E should be the ans.

Am i not right?

The question asks whether the range of {3, 4, 5, 6, x, y} is greater than 9.

It is not clear why are you subtracting x from the range of {3, 4, 5, 6, x, y}. We are not asked to find the difference between the range of {3, 4, 5, 6, x, y} and x.
_________________

Re: Is the range of the integers 6, 3, y, 4, 5, and x greater th [#permalink]

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25 Jul 2017, 00:29

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9 ?

(1) y > 3x (2) y > x > 3

take statement1: y>3x if x=3 then y>3*3=9 means y can take value as 10,11,12,13 ..... then range comes as 10-3=7 , or may be 10 Hence this statement alone is not sufficient take statement2: y > x > 3 , say x=4 and y=5 then range is 6-3=3 ; say x=4 and y=15 then range is 15-3=12 Hence this statement alone is not sufficient

Take both statement together:

from statement 2, it is clear that x can take value 4 or greater Say x=4 then from statement 1,y>3x means y>12 so Y can take value 13 or greater say Y=13 then range = highest value - lowest value in the set = 13- 3=10 sufficient