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29 Apr 2016, 02:40
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
66% (01:25) correct
34%
(01:31)
wrong
based on 250
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29 Apr 2016, 02:54
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Is x > 0?
(1) |3x−30|<20..
If we want to explain the given MOD in ONE line..
IT IS : 3x lies less than 20 places from 30 on the number line..
so 3x lies between 30-20 and 30+20 OR between 10 and 50
or x lies between 10/3 and 50/3
so surely x>0..
we can solve it also
|3x−30|<20..
3x-30<20.. 3x<50
x<50/3
|3x−30|<20..
3x-30>-20..
3x>10 or x>10/3
x lies between 10/3 and 50/3
SUFF
(2) 3x – 30 is greater than zero.
3x-30>0 or 3x>30, that is x>10
so x>0
Suff
D
(1) |3x−30|<20..
If we want to explain the given MOD in ONE line..
IT IS : 3x lies less than 20 places from 30 on the number line..
so 3x lies between 30-20 and 30+20 OR between 10 and 50
or x lies between 10/3 and 50/3
so surely x>0..
we can solve it also
|3x−30|<20..
3x-30<20.. 3x<50
x<50/3
|3x−30|<20..
3x-30>-20..
3x>10 or x>10/3
x lies between 10/3 and 50/3
SUFF
(2) 3x – 30 is greater than zero.
3x-30>0 or 3x>30, that is x>10
so x>0
Suff
D
General Discussion
29 Apr 2016, 12:31
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Bunuel
Is x > 0?
(1) |3x−30|<20
(2) 3x – 30 is greater than zero.
(1) |3x−30|<20
(2) 3x – 30 is greater than zero.
The plot for |3x-30| will be a 'V' and the lowest possible co-ordinate will be at (10,0).
Now we just have to find the y co-ordinate upto which x co-ordinates remain positive.
3x-30 always remains in the 1st quadrant and -(3x-30) crosses the y-axis and goes into the 2nd quadrant at y = 30. So x remains positive for all values for 0<y<30.
Thus each condition is able to tell us that x>0.
Answer D.
