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Vyshak
St1: x - 5 = 7x + 2 or 5 - x = 7x + 2
x = -7/6 or x = 3/8
Substitute the two values back in |x - 5| = 7x + 2. Only x = 3/8 is a valid value. Is x < 0? No
Sufficient

Answer: A

Hi Vyshak,

another way to look at the statement after you have got your values..
Since |x-5| is greater than or equal to 0...
7x+2 will also be > or = 0..
x will be >= -2/7...
-7/6 can be eliminated as it is <-2/7
so ONLY 3/8 is left..
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Is x < 0 ?

(1) |x - 5| = 7x + 2
(2) |x + 5| = |4x + 5|

Similar questions to practice:
is-x-0-1-x-3-4x-3-2-x-3-2x-127978.html
is-x-0-1-x-3-4x-3-2-x-1-2x-1-can-100357.html
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Vyshak
St1: x - 5 = 7x + 2 or 5 - x = 7x + 2
x = -7/6 or x = 3/8
Substitute the two values back in |x - 5| = 7x + 2. Only x = 3/8 is a valid value. Is x < 0? No
Sufficient

I am struggling to understand this step.....When i put -7/6 in Equn i am getting -37=-37...


Pls help :) :) :) :) :) :) :)

St2: Square on both sides --> x^2 + 10x + 25 = 16x^2 + 40x + 25
15x^2 + 30x = 0
x = 0 or x = -2
Substitute the 2 values back in the original equation. Both the values satisfy the equation. Is x < 0? Can be yes or no.
Not Sufficient

Answer: A

Please format your reply properly.

Vyshak has used the value of 3/8 as the value of -7/6 is not a valid option.

When you put -7/6 into the given equation |x-5| = 7x+2 ---> you get 37/6 on the LHS and you get -37/6 on the RHS. Thus this value of x=-7/6 is not a valid one.

Do note here that LHS has |x-5| and as |x|\(\geq\)0 for all x, LHS \(\neq\) -37/6 .

Hope this helps.
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Vyshak
St1: x - 5 = 7x + 2 or 5 - x = 7x + 2
x = -7/6 or x = 3/8
Substitute the two values back in |x - 5| = 7x + 2. Only x = 3/8 is a valid value. Is x < 0? No
Sufficient

I am struggling to understand this step.....When i put -7/6 in Equn i am getting -37=-37...


Pls help :) :) :) :) :) :) :)

St2: Square on both sides --> x^2 + 10x + 25 = 16x^2 + 40x + 25
15x^2 + 30x = 0
x = 0 or x = -2
Substitute the 2 values back in the original equation. Both the values satisfy the equation. Is x < 0? Can be yes or no.
Not Sufficient

Answer: A

Please format your reply properly.

Vyshak has used the value of 3/8 as the value of -7/6 is not a valid option.

When you put -7/6 into the given equation |x-5| = 7x+2 ---> you get 37/6 on the LHS and you get -37/6 on the RHS. Thus this value of x=-7/6 is not a valid one.

Do note here that LHS has |x-5| and as |x|\(\geq\)0 for all x, LHS \(\neq\) -37/6 .

Hope this helps.

Perfect ...........Thanks a lot......
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[quote="ArunpriyanJ"]

Hi arun..
Refer your PM ..
I hope the query is clear now..
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Thanks Bunuel. It really helped :)
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Hi Bunuel

Statement 1 is giving x = 3/8
Statement 2 is giving x = -2 or 0.

is it acceptable for Statements to contradict each other?

Bunuel
stonecold
Is x < 0 ?

(1) |x - 5| = 7x + 2
(2) |x + 5| = |4x + 5|

Similar questions to practice:
https://gmatclub.com/forum/is-x-0-1-x-3- ... 27978.html
https://gmatclub.com/forum/is-x-0-1-x-3- ... 00357.html
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gmatbusters
Hi Bunuel

Statement 1 is giving x = 3/8
Statement 2 is giving x = -2 or 0.

is it acceptable for Statements to contradict each other?

Bunuel
stonecold
Is x < 0 ?

(1) |x - 5| = 7x + 2
(2) |x + 5| = |4x + 5|

Similar questions to practice:
https://gmatclub.com/forum/is-x-0-1-x-3- ... 27978.html
https://gmatclub.com/forum/is-x-0-1-x-3- ... 00357.html

No, that's not acceptable. I explained this here: https://gmatclub.com/forum/is-x-216394.html#p2093126
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Is x > 0 ?
(1) |x–5|=7x+2
(2) |x–3|=|15x–3|

anyone help me in solving this!

Posted from my mobile device
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Jay181099
Is x > 0 ?
(1) |x–5|=7x+2
(2) |x–3|=|15x–3|

anyone help me in solving this!

Posted from my mobile device

I re-posted this question here: https://gmatclub.com/forum/is-x-0-1-x-5 ... l#p2759851 You can also find there a solution to it. Hope it helps.
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Statement 1

x-5 = 7x+2 or -(x-5) = 7x+2

on solving
x = -7/6 or x = 3/8

Always substitute the values (specifically while solving modulus)
x = -7/6 ; 37/8 =-37/8
x = 3/8 ; 23/6 = 23/6

Therefore, x = 3/8
Clearly answers x < 0?
Which is NO


Statement 2

Square on both sides.
x^2 + 10x + 25 = 16x^2 + 40x + 25......................[(a+b)^2 = a^2 + b^2 + 2ab]

on solving
x = 0 or x = -2

substitute the values
Both the values satisfy the equation. i.e. x = 0 or x = -2
Therefore, we can not clearly decipher if x < 0
As it can be a Yes or No.


Answer: A

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