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fresinha12
Is |x-1|< 1 ?

(1) (x-1)^2 <= 1

(2) x^2 - 1 > 0

1) x=1.5, but then |x-1|<1; if x=2 the |x-1|=1 so Insuff

2) x^2 >1
which means x<-1 or x>1

if x<0 then |x-1|>1 if x>1 could be 1.5 then |x-1|<1 so insuff

1 and 2 together; if x>1 say x=1.5 then |x-1|<1 if x=2 then |x-1|>1

E it is
correct,i overlooked <=1 :cry:
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jjhko
Is |x-1|< 1 ?

(1) (x-1)^2 <= 1
(2) x^2 - 1 > 0

1: -2 < x < 2. nsf
2: x < -1 or x > 1. x cannot be 1. nsf.

togather also insuff...

so //E//

Did you mean 0 <=x <=2 and hence nsf?
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scthakur
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jjhko
Is |x-1|< 1 ?

(1) (x-1)^2 <= 1
(2) x^2 - 1 > 0

1: -2 < x < 2. nsf
2: x < -1 or x > 1. x cannot be 1. nsf.

togather also insuff...

so //E//

Did you mean 0 <=x <=2 and hence nsf?
nope.

actually 1 is 1: 0 =< x =< 2. nsf

x can be as low as -2 and as high as 2. any value for x that ranges between these two ends satisfies the inequality: (x-1)^2 <= 1.
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GMAT TIGER

nope.

actually 1 is 1: -2 =< x =< 2. nsf

x can be as low as -2 and as high as 2. any value for x that ranges between these two ends satisfies the inequality: (x-1)^2 <= 1.


That is not true....for x = -2.....left side will be 9.....here x cannot be negative......
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scthakur
GMAT TIGER

nope.

actually 1 is 1: -2 =< x =< 2. nsf

x can be as low as -2 and as high as 2. any value for x that ranges between these two ends satisfies the inequality: (x-1)^2 <= 1.


That is not true....for x = -2.....left side will be 9.....here x cannot be negative......

you r right. thanks for the note.

thats actually 0 =< x =< 2.

why it is so easy to overlook so tiny issues that really matters. :twisted: :twisted: :twisted:



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