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05 May 2021, 23:00
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B
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Difficulty:
25%
(medium)
Question Stats:
76% (01:10) correct
24%
(01:05)
wrong
based on 80
sessions
History
Date
Time
Result
Not Attempted Yet
Is \(\sqrt[3] x\) non-negative?
(1) The product of x and positive integer g is not x.
(2) x is a prime number.
(1) The product of x and positive integer g is not x.
(2) x is a prime number.
05 May 2021, 23:10
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Bunuel
\(\sqrt[3] x\) will be non-negative, if x is non-negative.
(1) The product of x and positive integer g is not x.
Just tells us that g is not 1, and x is not 0.
But x can be negative or positive.
Insufficient
(2) x is a prime number.
So x is positive, and \(\sqrt[3] x\) will be positive
Sufficient
B
20 Sep 2021, 09:18
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Bunuel
S1: The product of x and positive integer g is not x (Not Sufficient)
1. Let's assume g to be 2
2. Now, if \(x = 2\) then \(x*g = 2*2\) ≠ x and \(\sqrt[3] x\) will be non-negative
3. On the other hand, if \(x = -9\) then \(x*g = -9*2\) ≠ x and \(\sqrt[3] x\) will be negative
S2: x is a prime number (Sufficient)
1. Prime numbers are always positive. The smallest prime number is \(2\)
2. Hence, \(\sqrt[3] x\) will be non-negative
Ans. B
