Hi

Bunuel,

Case (ii): x > x^2 --> 0 < x < 1 : I understand the solution from a value point of view (plugging negative & positive fractions). However, I tried to solve it algebraically as shown. Please guide as to where the loophole in my working lies:

x>x^2

x-x^2>0

x(1-x)>0

Hence, the terms could both be either positive or negative. If both are positive, you get the condition: 0 < x < 1

However, incase they are both negative -- x<0, x>1 -- That does not lead to the required condition.

Thanks!