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Bunuel
Is x – 2y + z greater than x + y – z?

(1) y is positive.
(2) z is negative.

First, in a quick glance, we can see that we can work on the formula

x - 2y + z > x + y - z (first we cancel the X)
-2y + z > y - z (now we separate the terms)
3y < 2z

Option 1 ( we only have the Y, which is positive, no clue about Z)
Option 2 (we only have Z, no clue about Y)

Combining we are going to arrive to the right answer.

Answer C
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1) ns

2) ns

1+2..

not sure about x sign ns

E
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mango aadmi
1) ns

2) ns

1+2..

not sure about x sign ns

E

first simplify the equation and then decide if the statements are suff or not
x - 2y + z > x + y - z
-2y + z > y - z
3y < 2z ..
so the Q finally asks us is 3y<2z...
this is possible only if z>y..

lets check the statements..

(1) y is positive.
no info on z... insuff

(2) z is negative.
no info on y.. insuff..

combined as z is -ive and y +ive...
y will always be greater than z..
so answer to our query is NO..
suff
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