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Parbe
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Is x >3? 1. (x-3)*(x-2)*(x-1) >0 2. x>1 A. 25 Sep 2007, 07:06
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Is x >3?

1. (x-3)*(x-2)*(x-1) >0
2. x>1



A. Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.



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Is x >3? 1. (x-3)*(x-2)*(x-1) >0 2. x>1 A. 25 Sep 2007, 09:08
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Is x >3 ?

meaning:

(x-3) > 0 ?

statement 1

(x-3)*(x-2)*(x-1) >0

(x-3),(x-2),(x-1) cannot all be < 0 since then (x-3)*(x-2)*(x-1) >0 is false.

(x-3),(x-2),(x-1) if only one of then < 0 then (x-3)*(x-2)*(x-1) >0 is false.

insufficient

statement 2

x > 1

meaning

(x-1) > 0

insufficient

both statements

(x-1) > 0

(x-3)*(x-2)*(x-1) >0

still dosen't solve our problem since (x-3) can be negative or positive.

the answer is (E)

:)
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Is x >3? 1. (x-3)*(x-2)*(x-1) >0 2. x>1 A. 25 Sep 2007, 09:58
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Parbe
Is x >3?

1. (x-3)*(x-2)*(x-1) >0
2. x>1



A. Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
Show more


I'm getting A.

Stat 1.
Since (x-3)*(x-2)*(x-1) >0, x cannot equal 3, 2 or 1.
Further, x cannot be 0 or -ve (-ve*-ve*-ve = -ve, which is less than 0, which is not possible)

Therefore, x has to be a positive value greater than 3. Sufficient.

Stat 2.
x=2; no
x=4; yes
Insuff.
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Is x >3? 1. (x-3)*(x-2)*(x-1) >0 2. x>1 A. 25 Sep 2007, 10:02
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GK_Gmat
Parbe
Is x >3?

1. (x-3)*(x-2)*(x-1) >0
2. x>1



A. Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

I'm getting A.

Stat 1.
Since (x-3)*(x-2)*(x-1) >0, x cannot equal 3, 2 or 1.
Further, x cannot be 0 or -ve (-ve*-ve*-ve = -ve, which is less than 0, which is not possible)

Therefore, x has to be a positive value greater than 3. Sufficient.

Stat 2.
x=2; no
x=4; yes
Insuff.
Show more


What about x = 3/2 ?

(3/2-6/2)*(3/2-4/2)*(3/2-2/2) = -3/2*-1/2*1/2 = 3/8

:?
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Is x >3? 1. (x-3)*(x-2)*(x-1) >0 2. x>1 A. 25 Sep 2007, 12:56
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GK_Gmat,

For statement 1 if you pick up
X=1.5 then it becomes clear that :
(x-1) >0
(x-2) <0
(x-3) <0
Resulting in :
(x-3)*(x-2)*(x-1) >0

If you pick up X= 4, then (x-3)*(x-2)*(x-1) >0 as well.
=> INSUFF
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Is x >3? 1. (x-3)*(x-2)*(x-1) >0 2. x>1 A. 25 Sep 2007, 14:57
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Parbe
Is x >3?

1. (x-3)*(x-2)*(x-1) >0
2. x>1



A. Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
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The stem doesnt say whether X is integer or not, so it can be 1.5. Thus, E.
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Is x >3? 1. (x-3)*(x-2)*(x-1) >0 2. x>1 A. 25 Sep 2007, 19:12
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St1:
(x-3)*(x-2)*(x-1) >0
Valid range for x:
x > 3 or 1<x<2

insufficient.

St2:
insufficient.

Using both, still insufficient as x could take either >3 range or 1<x<2 range.

Ans E
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Is x >3? 1. (x-3)*(x-2)*(x-1) >0 2. x>1 A. 25 Sep 2007, 19:29
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Parbe
Is x >3?

1. (x-3)*(x-2)*(x-1) >0
2. x>1



A. Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
Show more


Always go for the easier stmnt first to elim answer choices in case u gotta move on.

S2: x>1. well X could be 4 or it could be 1 1/2 Insuff.

S1: (x-3)(x-2)(x-1)>0 Notice that these are going to be consecutive integers.

now use some values here, think about what would make the stmnt 2 true, but not x>3 true, b/c u can obviously find many values for which x>3 and S2 is true.

try x= 1 1/2. This gives us two negatives and one positive:

(-1.5)(-.5)(.5)>0 This is greater than 0 b/c the negs cancel.

Insuff x could be less than 3 or greater than 3.

S1 and S2:

using 1 1/2 again, satisfies both statements and gives us a situation in which X<3. Knowing we could apply many + values that are greater than 3 leaves these combined statements insuff.


Answer E.
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GK_Gmat
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Is x >3? 1. (x-3)*(x-2)*(x-1) >0 2. x>1 A. 25 Sep 2007, 23:59
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KillerSquirrel
GK_Gmat
Parbe
Is x >3?

1. (x-3)*(x-2)*(x-1) >0
2. x>1



A. Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

I'm getting A.

Stat 1.
Since (x-3)*(x-2)*(x-1) >0, x cannot equal 3, 2 or 1.
Further, x cannot be 0 or -ve (-ve*-ve*-ve = -ve, which is less than 0, which is not possible)

Therefore, x has to be a positive value greater than 3. Sufficient.

Stat 2.
x=2; no
x=4; yes
Insuff.

What about x = 3/2 ?

(3/2-6/2)*(3/2-4/2)*(3/2-2/2) = -3/2*-1/2*1/2 = 3/8

:?
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Damn it! Didn't try non-integer values!!! Thanks for the correction.



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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