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02 Mar 2022, 05:00
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
47% (01:40) correct
53%
(01:48)
wrong
based on 78
sessions
History
Date
Time
Result
Not Attempted Yet
Is x > 6?
(1) x/y > 1.4
(2) The average of x and y is 2
Are You Up For the Challenge: 700 Level Questions
(1) x/y > 1.4
(2) The average of x and y is 2
Are You Up For the Challenge: 700 Level Questions
02 Mar 2022, 23:17
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Bunuel
Question: Is x > 6?
STatement 1: x/y > 1.4
i.e x > 1.4y
But the value of y or x is still unknown hence
NOT SUFFICIENT
Statement 2: \(\frac{x+y}{2} = 2\)
i.e. x+y = 4
But since y can be both negative and positive therefore x may be both greater than and less than 6 hence
NOT SUFFICIENT
COmbining the statements
\(\frac{x+y}{2} = 2\) i.e. x+y = 4 and x > 1.4y
i.e. for minimum value of x, @x = 1.4y, we get
2.4 y = 4
i.e. y = 4/2.4 = 1.67
i.e. x > 1.4*1.67
i.e. x > 2.33
But y can still be negative such as for y = -3, x = 7 (also x > 1.4y)
ie. x can still be greater than 6 hence
NOT SUFFICIENT
Answer: Option E
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03 Oct 2023, 09:22
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GMATinsight
In the above solution, you write x > 1.4y. However, this only only true if y > 0. Else, x < 1.4y.
This makes it so that (7, -3) is NOT a correct solution, since it violates the first condition (i.e., x/y > 1.4)
From statement 1, x and y have the same sign
From statement 2, at most ONE out of x or y is negative (both can't be negative since x + y = 4)
Therefore combining both statements, we get x,y > 0
=> y < 4 (since x = 4 - y and x > 0)
=> x < 4 . SUFFICIENT.
Hence, the OA is correct, and the answer is C.
