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rahul16singh28
Joined: 31 Jul 2017
Last visit: 09 Jun 2020
Posts: 428
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Given Kudos: 752
Location: Malaysia
Schools: INSEAD Jan '19
GPA: 3.95
WE:Consulting (Energy)
Updated on: 11 Sep 2017, 07:50
Originally posted by rahul16singh28 on 11 Sep 2017, 01:19.
Last edited by chetan2u on 11 Sep 2017, 07:50, edited 1 time in total.
Last edited by chetan2u on 11 Sep 2017, 07:50, edited 1 time in total.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
33% (01:43) correct
67%
(02:25)
wrong
based on 12
sessions
History
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Time
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Not Attempted Yet
Hi All,
Need help on the below question. Would be great if someone can tell me where I am wrong in this. Not Sure of the Difficulty level..
Is X^(a+b) > X^(a-b) if both a and b are positive integers?
(1) X^(a+1) > X^(a-1)
(2) a = b + 2
Need help on the below question. Would be great if someone can tell me where I am wrong in this. Not Sure of the Difficulty level..
Is X^(a+b) > X^(a-b) if both a and b are positive integers?
(1) X^(a+1) > X^(a-1)
(2) a = b + 2
From the question can we deduce that we need to find X^(2b)>1 - Am I right on this??
Stamnt 1:
X^2 > 1
X^(2b) > 1^(b)
So, X^(2b) > 1 - Sufficient
Stamnt 2:
Insufficient.
Please tell me where I am going wrong on this :(
Bunuel - Your help would be great on this. :-)
Thanks
Stamnt 1:
X^2 > 1
X^(2b) > 1^(b)
So, X^(2b) > 1 - Sufficient
Stamnt 2:
Insufficient.
Please tell me where I am going wrong on this :(
Bunuel - Your help would be great on this. :-)
Thanks
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
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11 Sep 2017, 08:29
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rahul16singh28
Hi...
\(x^{a+b}>x^{a-b}\)
Let's see the statements..
\(X^{a+1}>x^{a-1}\)....
Let a=1, x=2..... x^2>x^1...
\(x^{a+b}>x^{a-b}......\)...ans YES
Let a=3,x=-2, ......(-2)^4>(-2)^2...
Let b=2..\(x^{a+b}>x^{a-b}........(-2)^{3+2}>(-2)^{3-2}......(-2)^5>(-2)^1......\) NO
So different answers possible
Insufficient
2)a=b+2
Clearly insuff
Combined
Still the value can vary depending on value of x
Insuff
E
12 Sep 2017, 00:05
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rahul16singh28
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
There are 3 variables and 0 equation. Thus the answer E is most likely.
\(x = 1\)
\(x^{a+b} = x^{a-b}\): The answer to the question is false.
\(x = 2, a =1, b =1\).
\(x^{a+b} > x^{a-b}\): The answer to the question is true.
Therefore, the answer is E as expected.
For cases where we need 3 more equations, such as original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 80 % chance that E is the answer, while C has 15% chance and A, B or D has 5% chance. Since E is most likely to be the answer using 1) and 2) together according to DS definition. Obviously there may be cases where the answer is A, B, C or D.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
