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# Is x an even integer? Assume n and p are integers.

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Joined: 02 Sep 2009
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Is x an even integer? Assume n and p are integers.  [#permalink]

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24 Oct 2017, 23:52
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15% (low)

Question Stats:

93% (00:52) correct 8% (00:23) wrong based on 55 sessions

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Is x an even integer? Assume n and p are integers.

(1) x = (n + p)^2
(2) x = 2n + 10p

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Re: Is x an even integer? Assume n and p are integers.  [#permalink]

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25 Oct 2017, 00:39
Option B

For st1
If n=1 and p=2 then x= 9. Odd
n=2 p=2; x=16. Even.
n=0 p=0; x = 0. Even
Clearly insufficient

From st2 x is even for any values of n and p. This is applicable for negative and zero for n and p. Hence sufficient

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Re: Is x an even integer? Assume n and p are integers.  [#permalink]

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30 Oct 2017, 09:17
(1) x = (n + p)^2
As even or odd nature of n & p is not known, hence n+p can be even or odd . hence Not sufficient
(2) x = 2n + 10p
x = 2(n+5p) , hence x is even.
Sufficient.
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Re: Is x an even integer? Assume n and p are integers.  [#permalink]

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31 Oct 2017, 12:23
Bunuel wrote:
Is x an even integer? Assume n and p are integers.

(1) x = (n + p)^2
(2) x = 2n + 10p

St 1, if n+p=odd number, then x will be odd, but if n+p is even, then it'll be even. We don't know if n or p are even or odd.
St 2, an even number times any integer will be even. Therefore 2n is even and 10p is even. Even + even = even. Sufficient.
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Re: Is x an even integer? Assume n and p are integers. &nbs [#permalink] 31 Oct 2017, 12:23
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