Forget the conventional way to solve DS questions.
We will solve this DS question using the variable approach.The first step of the Variable Approach: The first step and the priority is to modify and recheck the original condition and the question to suit the type of information given in the condition.To master the Variable Approach, visit
https://www.mathrevolution.com and check our lessons and proven techniques to score high in DS questions.
Learn the 3 steps. [Watch lessons on our website to master these 3 steps]
Step 1 of the Variable Approach: Modifying and rechecking the original condition and the question.
We have to find Is \(\frac{x}{y} = 1\). => \(\frac{x}{y} = 1\)
=> x = y
So, we have to find whether x = y?
Condition(1) tells us that \(\frac{x^3}{y^3} = 1\).=> \(x^3 = y^3\)
=> The third power of 'x' and 'y' will only be equal when x = y - Is x = y -
YESSince the answer is a unique YES , condition(1) alone is sufficient by CMT 1.Condition(2) tells us that \(\frac{x^2}{y^2} = 1\).=> \(x^2 = y^2\)
=> Since, 'x' and 'y' are raised to an even power, even the negative number raised to even power will give positive values and x could be equal to y or -y.
Since the answer is not a unique YES or NO , condition(2) alone is not sufficient by CMT 1. Condition(1) alone is sufficient.So, A is the correct answer.Answer: ASAVE TIME: By Variable Approach[MODIFICATION], check the condition quickly and separately and mark answer as A or B.