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leonidas
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aim2010
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elmagnifico
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leonidas
Is │x│=│y│?
(1) x - y = 6
(2) x + y = 0

B.

(1) x - y = 6
x = y + 6

x = 0, y = -6
x = 5, y = -1

so insuff..
(2) x + y = 0
x = - y
so lxl = lyl
suff.

S2 is clearly sufficient. But lets examine S1. If x=y+6, that clearly states that X>Y, always. Doesnt this statement answer the question that x will not equal -y?
S1 should be sufficient as well, no?
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leonidas
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Thanks guys...... Here is what I got out of your posts:

To find wheather, x-y=0 or x+y=0 (Yes or No question)

Statement I is self-exlanatory, considering statement II,

The values (x,y) => (0,-6) and (5,-1) is not much useful to prove otherwise.

The values (3,-3) and say (9,3) will be useful.
Both the above x and y values meet the condition of x-y=6, but only (3,-3) meets the condition x+y=0 whereas (9,3) does not. Hence we get Yes and No.
There for insufficent.
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Greenberg
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Its best to solve absolute value problems as "distance on the number line" problems.

What you are being asked is "is the distance of x from 0 on the number line is equal to the distance of y from 0 on the same line".

This can only be true when x=-y or y=-x or x=y or

hence statement (1) is useless and statement (2) will give you the right answer (Yes)

:)
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leonidas
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Greenberg
Its best to solve absolute value problems as "distance on the number line" problems.

What you are being asked is "is the distance of x from 0 on the number line is equal to the distance of y from 0 on the same line".

This can only be true when x=-y or y=-x or x=y or

hence statement (1) is useless and statement (2) will give you the right answer (Yes)

:)

I agree. viewing it as a distance makes it always easier. I have a habit of complicating things :(
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elmagnifico
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leonidas
Is │x│=│y│?
(1) x - y = 6
(2) x + y = 0

B.

(1) x - y = 6
x = y + 6

x = 0, y = -6
x = 3, y = -3
x = 5, y = -1

so insuff..
(2) x + y = 0
x = - y
so lxl = lyl
suff.

S2 is clearly sufficient. But lets examine S1. If x=y+6, that clearly states that X>Y, always. Doesnt this statement answer the question that x will not equal -y?
S1 should be sufficient as well, no?

if x = 3 and x = -3, x = y+6.

in this case lxl = lyl = 3
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if statement one was x-y=0. Will that be sufficient ? as x = y and |x| = |y|



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