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Is x/y < 0?

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Is x/y < 0?  [#permalink]

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New post 14 Aug 2017, 05:54
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

85% (01:21) correct 15% (01:40) wrong based on 93 sessions

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Re: Is x/y < 0?  [#permalink]

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New post 14 Aug 2017, 06:01
Bunuel wrote:
Is x/y < 0?

(1) x^2 - 4x + 3 = 0
(2) y^2 – y – 6 = 0



Individual statements are not enough as each of the statement gives us the value of one variable involved.
Solving the two equations,
x = 1 or 3
y = -2 or 3

Combining the information from both the statements,
Because we have one value for y which is not negative, the expression x/y could be positive or negative(Insufficient)(Option E)
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Re: Is x/y < 0?  [#permalink]

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New post 24 Aug 2017, 13:41
Bunuel wrote:
Is x/y < 0?

(1) x^2 - 4x + 3 = 0
(2) y^2 – y – 6 = 0


We need to determine whether x/y < 0. If xy < 0, then the values of x and y have opposite signs. That is, either x is positive and y is negative or x is negative and y is positive.

Statement One Alone:

x^2 - 4x + 3 = 0

x^2 - 4x + 3 = 0

(x - 3)(x - 1) = 0

x = 3 or x = 1

Since we know nothing about y, statement one alone is not sufficient to answer the question.

Statement Two Alone:

y^2 – y – 6 = 0

y^2 – y – 6 = 0

(y + 2)(y - 3) = 0

y = -2 or y = 3

Since we know nothing about x, statement two alone is not sufficient to answer the question.

Statements One and Two Together:

Using statements one and two, we know that x = 3 or x = 1 and y = -2 or y = 3. If x = 3 and y = 3, then x/y is positive, and if x = 3 and y = -2, then x/y is negative. The two statements together are not sufficient to answer the question.

Answer: E
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Re: Is x/y < 0?   [#permalink] 24 Aug 2017, 13:41
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