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17 Nov 2022, 02:30
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
38% (01:15) correct
62%
(01:03)
wrong
based on 114
sessions
History
Date
Time
Result
Not Attempted Yet
Is x + y an odd integer?
(1) x is an odd integer
(2) x - y is an even integer
(1) x is an odd integer
(2) x - y is an even integer
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17 Nov 2022, 05:04
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Bunuel
Statement 1
x is an odd integer
We do not have any information on y, hence we cannot comment on the nature of x + y.
The information is not sufficient and we can rule out A and D.
Statement 2
x - y is an even integer
We know the difference is an even integer, however we are not aware of the nature of the x and y themselves. Hence we cannot comment on the nature of x + y. To understand this, let's take the following examples -
Case 1: x = y = \(\frac{2}{3}\)
\(\frac{2}{3} - \frac{2}{3} = 0\)
x + y = \(\frac{2}{3} + \frac{2}{3}\) = \(\frac{4}{3}\)
Is x + y odd integer -- No !
Case 2: x = \(\frac{3}{2 }\); y = \(\frac{-1}{2}\)
\(x - y = \frac{3}{2} + \frac{1}{2} = \frac{4}{2} = 2\)
\(x + y = \frac{3}{2} - \frac{1}{2} = \frac{2}{2} = 1\)
Is x + y = odd -- Yes !
As we have two possible answers, statement 2 doesn't help as well.
We can eliminate B.
Combined
We know x is an odd integer.
x - y = even integer
y = odd integer - even integer
y = odd integer
Is x + y an odd integer? - No !
Option C
General Discussion
13 Feb 2024, 03:43
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Can someone please post the Explanation here pls..
