Is x |y| y^2? (1) x y (2) y 0

Question

Is x·|y| > y^2?

(1) x > y

(2) y > 0

bigtreezl · Answer

E, I think

x-lyl-y^2>0?

1)x>y

say x=-1, y=-2

then -1-2-4> 0? no

say x=5, y=-1

then 5-1-1>0? yes

insuff.

2) y>0

will yeild the same results because we are taking the absolute value of y and the square of y, so y ends up being greater than 0 regardless

together

same results, insuff

Hades · Answer

Question: (x|y|>y^{2}?)

Question: (x>\frac{y^{2}}{|y|}?)

Question: (x>\frac{y}{|y|}y?)

Case 1: y>0  \longrightarrow (x>y?)  
Case 2: y<0  \longrightarrow (x>-y?) \longrightarrow x+y>0? 
 
(1)  x>y  INSUFFICIENT

(2)  y>0  INSUFFICIENT

Together sufficient as they're both positive

bigtreezl · Answer

is this x minus lyl or x times lyl ?

i thought it was minus

mdfrahim · Answer

We agree that alone none is suff.

Lets combine....due to stmt. b we can say that both X and Y are +ve.
From stmt a we can say that X = A + Y.
So the question becomes...
Is (A+Y) * Y > Y^2
Is (AY + Y^2) > Y^2.........and this is clearly true.

Hence C.

tkarthi4u · Answer

Is x·|y| > y^2?

stmt 1 : x > y

when x and y are +ve x = 4 and y = 3. 12 > 9
when x and y are -ve y = -3 and x = 4 12 >9
 y = -3 and x = -2 6 0 . Not sure of x insuff

togther yes x >y and y >0 tell x >0 and hence sufficient.

bb · Answer

Misplaced Post - user warning issued

PhilosophusRex · Answer

C is the correct answer, for the reasons given above.

How hard is this question by the way? At what scorelevel can you expect to see such questions?

Hades · Answer

Not terribly, I'd say a mid 40 Q

You can always get the answer by plugging in some values

Is x |y| > y^2? (1) x > y (2) y > 0

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