It is currently 21 Feb 2018, 12:47

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Is x |y| > y^2? (1) x > y (2) y > 0

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Manager
Joined: 10 May 2009
Posts: 65
Is x |y| > y^2? (1) x > y (2) y > 0 [#permalink]

### Show Tags

08 Jun 2009, 05:37
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is x·|y| > y^2?

(1) x > y

(2) y > 0
Director
Joined: 23 May 2008
Posts: 799
Re: Tough DS [#permalink]

### Show Tags

08 Jun 2009, 10:12
prinits wrote:
Is x·|y| > y^2?

(1) x > y

(2) y > 0

E, I think

x-lyl-y^2>0?

1)x>y

say x=-1, y=-2

then -1-2-4> 0? no

say x=5, y=-1

then 5-1-1>0? yes

insuff.

2) y>0

will yeild the same results because we are taking the absolute value of y and the square of y, so y ends up being greater than 0 regardless

together

same results, insuff
Manager
Joined: 13 May 2009
Posts: 191
Schools: Stanford, Harvard, Berkeley, INSEAD
Re: Tough DS [#permalink]

### Show Tags

08 Jun 2009, 16:06
prinits wrote:
Is x·|y| > y^2?

(1) x > y

(2) y > 0

Question:$$(x|y|>y^{2}?)$$

Question:$$(x>\frac{y^{2}}{|y|}?)$$

Question:$$(x>\frac{y}{|y|}y?)$$

Case 1: y>0 $$\longrightarrow (x>y?)$$
Case 2: y<0 $$\longrightarrow (x>-y?) \longrightarrow x+y>0?$$

(1) $$x>y$$ INSUFFICIENT

(2) $$y>0$$ INSUFFICIENT

Together sufficient as they're both positive
_________________

Director
Joined: 23 May 2008
Posts: 799
Re: Tough DS [#permalink]

### Show Tags

08 Jun 2009, 16:40
prinits wrote:
Is x·|y| > y^2?

(1) x > y

(2) y > 0

is this x minus lyl or x times lyl ?

i thought it was minus
Manager
Joined: 28 Jan 2004
Posts: 201
Location: India
Re: Tough DS [#permalink]

### Show Tags

08 Jun 2009, 17:28
We agree that alone none is suff.

Lets combine....due to stmt. b we can say that both X and Y are +ve.
From stmt a we can say that X = A + Y.
So the question becomes...
Is (A+Y) * Y > Y^2
Is (AY + Y^2) > Y^2.........and this is clearly true.

Hence C.
Senior Manager
Joined: 08 Jan 2009
Posts: 324
Re: Tough DS [#permalink]

### Show Tags

08 Jun 2009, 19:02
Is x·|y| > y^2?

stmt 1 : x > y

when x and y are +ve x = 4 and y = 3. 12 > 9
when x and y are -ve y = -3 and x = 4 12 >9
y = -3 and x = -2 6 < 9
Insufficient.

stmt 2 : y >0 . Not sure of x insuff

togther yes x >y and y >0 tell x >0 and hence sufficient.
Founder
Joined: 04 Dec 2002
Posts: 16498
Location: United States (WA)
GMAT 1: 750 Q49 V42
Re: Tough DS [#permalink]

### Show Tags

10 Jun 2009, 17:37
prinits wrote:
Is x·|y| > y^2?

(1) x > y

(2) y > 0

Misplaced Post - user warning issued
_________________

Founder of GMAT Club

Just starting out with GMAT? Start here... or use our Daily Study Plan

Co-author of the GMAT Club tests

Intern
Joined: 10 Jun 2009
Posts: 29
Location: Stockholm, Sweden
Re: Tough DS [#permalink]

### Show Tags

11 Jun 2009, 00:00
C is the correct answer, for the reasons given above.

How hard is this question by the way? At what scorelevel can you expect to see such questions?
Manager
Joined: 13 May 2009
Posts: 191
Schools: Stanford, Harvard, Berkeley, INSEAD
Re: Tough DS [#permalink]

### Show Tags

11 Jun 2009, 00:07
Not terribly, I'd say a mid 40 Q

You can always get the answer by plugging in some values
_________________

Re: Tough DS   [#permalink] 11 Jun 2009, 00:07
Display posts from previous: Sort by

# Is x |y| > y^2? (1) x > y (2) y > 0

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.