It is currently 21 Oct 2017, 11:02

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a

Author Message
Senior Manager
Joined: 29 Aug 2005
Posts: 272

Kudos [?]: 69 [0], given: 0

Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a [#permalink]

### Show Tags

19 Jun 2008, 04:50
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?
_________________

The world is continuous, but the mind is discrete

Kudos [?]: 69 [0], given: 0

Director
Joined: 14 Aug 2007
Posts: 726

Kudos [?]: 212 [0], given: 0

### Show Tags

19 Jun 2008, 06:29
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

IMHO, it should be B

If its sure that x+y>z , and question is asking the same, why to bother if z+y>x or not?

Kudos [?]: 212 [0], given: 0

Manager
Joined: 16 Mar 2008
Posts: 66

Kudos [?]: 7 [0], given: 0

### Show Tags

19 Jun 2008, 06:34
B .... sum of the two sides of a triangle is greater than the third side.

Kudos [?]: 7 [0], given: 0

Senior Manager
Joined: 29 Aug 2005
Posts: 272

Kudos [?]: 69 [0], given: 0

### Show Tags

19 Jun 2008, 23:12
alpha_plus_gamma wrote:
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

IMHO, it should be B

If its sure that x+y>z , and question is asking the same, why to bother if z+y>x or not?

See my point is that yes surely x+y>z is inferable, but equally infereable is z+y>x , then why not that option
the idea is that this option brings in two different possibilities, and hence the option is insufficent to answer the question.

therefore this statement is insufficent.

so shdnt the answer be E on this

Can some more guys give thier opinion on this

Thanks
_________________

The world is continuous, but the mind is discrete

Kudos [?]: 69 [0], given: 0

Manager
Joined: 22 May 2007
Posts: 218

Kudos [?]: 126 [0], given: 0

### Show Tags

19 Jun 2008, 23:33
I think all x+y>z has to be true if x,y,z are the sides of the triangle. I agree that y+z>x and z+y>x are also true. But the question stem specifically asks for x+y. Hence B. what's the OA on this?

Kudos [?]: 126 [0], given: 0

CEO
Joined: 17 May 2007
Posts: 2947

Kudos [?]: 667 [0], given: 210

### Show Tags

20 Jun 2008, 03:58
You're right
z+y > x and also x+z > y and finally x+y > z if they are three sides of a triangle.

Hence B is sufficient.

vdhawan1 wrote:
See my point is that yes surely x+y>z is inferable, but equally infereable is z+y>x , then why not that option
the idea is that this option brings in two different possibilities, and hence the option is insufficent to answer the question.

therefore this statement is insufficent.

so shdnt the answer be E on this

Can some more guys give thier opinion on this

Thanks

Kudos [?]: 667 [0], given: 210

VP
Joined: 18 May 2008
Posts: 1258

Kudos [?]: 527 [0], given: 0

### Show Tags

20 Jun 2008, 04:08
See take it this way.
let the three sides of triangle be x,y and z respectively
x+y>z
x+z>y
y+z>x
All three conditions are true.
We are asked abt 1 of them which ios definitely true. so it should be B only

Kudos [?]: 527 [0], given: 0

Manager
Joined: 31 Jul 2006
Posts: 233

Kudos [?]: 93 [0], given: 0

### Show Tags

21 Jun 2008, 07:21
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

Clearly, x+y will always be greater than z
x+z can also be greater than y, and y and z will also always be greater than x
either way, with these 3 facts, we can already answer the question

Kudos [?]: 93 [0], given: 0

Current Student
Joined: 11 May 2008
Posts: 555

Kudos [?]: 222 [0], given: 0

### Show Tags

08 Aug 2008, 04:06
here from option B we can say x+y>z. but there is a difference betn saying
a)x+y>z and
b) only x+y>z

Kudos [?]: 222 [0], given: 0

SVP
Joined: 07 Nov 2007
Posts: 1792

Kudos [?]: 1062 [0], given: 5

Location: New York

### Show Tags

08 Aug 2008, 07:23
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

Clear B...

_________________

Smiling wins more friends than frowning

Kudos [?]: 1062 [0], given: 5

VP
Joined: 17 Jun 2008
Posts: 1374

Kudos [?]: 406 [0], given: 0

### Show Tags

08 Aug 2008, 21:00
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

IMO B
(1) is in insuffi ->
x^2+y^2 = (x+y)^2-2xy
(x+y)^2-2xy-z^2>0 => x,y signs and values matter here in boh the cases when z<x+y or z>x+y

(2) is sufficient since properties of triangle

sum of two sides is greater than the third side
IMO B
_________________

cheers
Its Now Or Never

Kudos [?]: 406 [0], given: 0

Senior Manager
Joined: 06 Apr 2008
Posts: 429

Kudos [?]: 165 [0], given: 1

### Show Tags

08 Aug 2008, 23:28
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

IMO B)

Statement 1) conflicts when you change from +ve to -ve

Statement 2) is perfect

Kudos [?]: 165 [0], given: 1

Re: DS question   [#permalink] 08 Aug 2008, 23:28
Display posts from previous: Sort by