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# Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a

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Senior Manager
Joined: 29 Aug 2005
Posts: 266
Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a [#permalink]

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19 Jun 2008, 04:50
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Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?
_________________

The world is continuous, but the mind is discrete

Director
Joined: 14 Aug 2007
Posts: 704
Re: DS question [#permalink]

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19 Jun 2008, 06:29
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

IMHO, it should be B

If its sure that x+y>z , and question is asking the same, why to bother if z+y>x or not?
Manager
Joined: 16 Mar 2008
Posts: 65
Re: DS question [#permalink]

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19 Jun 2008, 06:34
B .... sum of the two sides of a triangle is greater than the third side.
Senior Manager
Joined: 29 Aug 2005
Posts: 266
Re: DS question [#permalink]

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19 Jun 2008, 23:12
alpha_plus_gamma wrote:
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

IMHO, it should be B

If its sure that x+y>z , and question is asking the same, why to bother if z+y>x or not?

See my point is that yes surely x+y>z is inferable, but equally infereable is z+y>x , then why not that option
the idea is that this option brings in two different possibilities, and hence the option is insufficent to answer the question.

therefore this statement is insufficent.

so shdnt the answer be E on this

Can some more guys give thier opinion on this

Thanks
_________________

The world is continuous, but the mind is discrete

Manager
Joined: 22 May 2007
Posts: 213
Re: DS question [#permalink]

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19 Jun 2008, 23:33
I think all x+y>z has to be true if x,y,z are the sides of the triangle. I agree that y+z>x and z+y>x are also true. But the question stem specifically asks for x+y. Hence B. what's the OA on this?
CEO
Joined: 17 May 2007
Posts: 2917
Re: DS question [#permalink]

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20 Jun 2008, 03:58
You're right
z+y > x and also x+z > y and finally x+y > z if they are three sides of a triangle.

Hence B is sufficient.

vdhawan1 wrote:
See my point is that yes surely x+y>z is inferable, but equally infereable is z+y>x , then why not that option
the idea is that this option brings in two different possibilities, and hence the option is insufficent to answer the question.

therefore this statement is insufficent.

so shdnt the answer be E on this

Can some more guys give thier opinion on this

Thanks
VP
Joined: 18 May 2008
Posts: 1203
Re: DS question [#permalink]

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20 Jun 2008, 04:08
The answer is definitely B.
See take it this way.
let the three sides of triangle be x,y and z respectively
x+y>z
x+z>y
y+z>x
All three conditions are true.
We are asked abt 1 of them which ios definitely true. so it should be B only
Manager
Joined: 31 Jul 2006
Posts: 226
Re: DS question [#permalink]

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21 Jun 2008, 07:21
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

Clearly, x+y will always be greater than z
x+z can also be greater than y, and y and z will also always be greater than x
either way, with these 3 facts, we can already answer the question
Current Student
Joined: 11 May 2008
Posts: 552
Re: DS question [#permalink]

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08 Aug 2008, 04:06
here from option B we can say x+y>z. but there is a difference betn saying
a)x+y>z and
b) only x+y>z
SVP
Joined: 07 Nov 2007
Posts: 1761
Location: New York
Re: DS question [#permalink]

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08 Aug 2008, 07:23
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

Clear B...

Question Asked.. is x+y>z?... answer is yes.. then B is suffcient..
_________________

Smiling wins more friends than frowning

VP
Joined: 17 Jun 2008
Posts: 1325
Re: DS question [#permalink]

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08 Aug 2008, 21:00
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

IMO B
(1) is in insuffi ->
x^2+y^2 = (x+y)^2-2xy
(x+y)^2-2xy-z^2>0 => x,y signs and values matter here in boh the cases when z<x+y or z>x+y

(2) is sufficient since properties of triangle

sum of two sides is greater than the third side
IMO B
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cheers
Its Now Or Never

Senior Manager
Joined: 06 Apr 2008
Posts: 401
Re: DS question [#permalink]

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08 Aug 2008, 23:28
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

IMO B)

Statement 1) conflicts when you change from +ve to -ve

Statement 2) is perfect
Re: DS question   [#permalink] 08 Aug 2008, 23:28
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# Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a

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