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vd
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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a 19 Jun 2008, 04:50
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Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?



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alpha_plus_gamma
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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a 19 Jun 2008, 06:29
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vdhawan1
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?
Show more

IMHO, it should be B

If its sure that x+y>z , and question is asking the same, why to bother if z+y>x or not?
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gmat2ndtime
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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a 19 Jun 2008, 06:34
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B .... sum of the two sides of a triangle is greater than the third side.
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vd
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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a 19 Jun 2008, 23:12
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alpha_plus_gamma
vdhawan1
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

IMHO, it should be B

If its sure that x+y>z , and question is asking the same, why to bother if z+y>x or not?
Show more

See my point is that yes surely x+y>z is inferable, but equally infereable is z+y>x , then why not that option
the idea is that this option brings in two different possibilities, and hence the option is insufficent to answer the question.

therefore this statement is insufficent.

so shdnt the answer be E on this

Can some more guys give thier opinion on this

Thanks
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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a 19 Jun 2008, 23:33
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I think all x+y>z has to be true if x,y,z are the sides of the triangle. I agree that y+z>x and z+y>x are also true. But the question stem specifically asks for x+y. Hence B. what's the OA on this?
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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a 20 Jun 2008, 03:58
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You're right
z+y > x and also x+z > y and finally x+y > z if they are three sides of a triangle.

Hence B is sufficient.

vdhawan1

See my point is that yes surely x+y>z is inferable, but equally infereable is z+y>x , then why not that option
the idea is that this option brings in two different possibilities, and hence the option is insufficent to answer the question.

therefore this statement is insufficent.

so shdnt the answer be E on this

Can some more guys give thier opinion on this

Thanks
Show more
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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a 20 Jun 2008, 04:08
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The answer is definitely B.
See take it this way.
let the three sides of triangle be x,y and z respectively
x+y>z
x+z>y
y+z>x
All three conditions are true.
We are asked abt 1 of them which ios definitely true. so it should be B only
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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a 21 Jun 2008, 07:21
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vdhawan1
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?
Show more
Clearly, x+y will always be greater than z
x+z can also be greater than y, and y and z will also always be greater than x
either way, with these 3 facts, we can already answer the question
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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a 08 Aug 2008, 04:06
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here from option B we can say x+y>z. but there is a difference betn saying
a)x+y>z and
b) only x+y>z
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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a 08 Aug 2008, 07:23
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vdhawan1
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?
Show more

Clear B...

Question Asked.. is x+y>z?... answer is yes.. then B is suffcient..
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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a 08 Aug 2008, 21:00
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vdhawan1
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?
Show more

IMO B
(1) is in insuffi ->
x^2+y^2 = (x+y)^2-2xy
(x+y)^2-2xy-z^2>0 => x,y signs and values matter here in boh the cases when z<x+y or z>x+y

(2) is sufficient since properties of triangle

sum of two sides is greater than the third side
IMO B
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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a 08 Aug 2008, 23:28
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vdhawan1
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?
Show more

IMO B)

Statement 1) conflicts when you change from +ve to -ve

Statement 2) is perfect



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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