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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a [#permalink]
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19 Jun 2008, 04:50
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This topic is locked. If you want to discuss this question please repost it in the respective forum. Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a triangle statement 1 is clearly not sufficient from statement 2 it can follow that x+y>z but it can equally follow that z+y>x hence insufficient both statements put together also don’t help so answer should be E on this However, the OA is different Want to have u r opinion guys. Can u please tell me where I am wrong on this?
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Re: DS question [#permalink]
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19 Jun 2008, 06:29
vdhawan1 wrote: Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a triangle
statement 1 is clearly not sufficient from statement 2 it can follow that x+y>z but it can equally follow that z+y>x hence insufficient
both statements put together also don’t help so answer should be E on this However, the OA is different Want to have u r opinion guys. Can u please tell me where I am wrong on this? IMHO, it should be B If its sure that x+y>z , and question is asking the same, why to bother if z+y>x or not?



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Re: DS question [#permalink]
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19 Jun 2008, 06:34
B .... sum of the two sides of a triangle is greater than the third side.



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Re: DS question [#permalink]
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19 Jun 2008, 23:12
alpha_plus_gamma wrote: vdhawan1 wrote: Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a triangle
statement 1 is clearly not sufficient from statement 2 it can follow that x+y>z but it can equally follow that z+y>x hence insufficient
both statements put together also don’t help so answer should be E on this However, the OA is different Want to have u r opinion guys. Can u please tell me where I am wrong on this? IMHO, it should be B If its sure that x+y>z , and question is asking the same, why to bother if z+y>x or not? See my point is that yes surely x+y>z is inferable, but equally infereable is z+y>x , then why not that option the idea is that this option brings in two different possibilities, and hence the option is insufficent to answer the question. therefore this statement is insufficent. so shdnt the answer be E on this Can some more guys give thier opinion on this Thanks
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Re: DS question [#permalink]
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19 Jun 2008, 23:33
I think all x+y>z has to be true if x,y,z are the sides of the triangle. I agree that y+z>x and z+y>x are also true. But the question stem specifically asks for x+y. Hence B. what's the OA on this?



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Re: DS question [#permalink]
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20 Jun 2008, 03:58
You're right z+y > x and also x+z > y and finally x+y > z if they are three sides of a triangle. Hence B is sufficient. vdhawan1 wrote: See my point is that yes surely x+y>z is inferable, but equally infereable is z+y>x , then why not that option the idea is that this option brings in two different possibilities, and hence the option is insufficent to answer the question.
therefore this statement is insufficent.
so shdnt the answer be E on this
Can some more guys give thier opinion on this
Thanks



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Re: DS question [#permalink]
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20 Jun 2008, 04:08
The answer is definitely B. See take it this way. let the three sides of triangle be x,y and z respectively x+y>z x+z>y y+z>x All three conditions are true. We are asked abt 1 of them which ios definitely true. so it should be B only



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Re: DS question [#permalink]
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21 Jun 2008, 07:21
vdhawan1 wrote: Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a triangle
statement 1 is clearly not sufficient from statement 2 it can follow that x+y>z but it can equally follow that z+y>x hence insufficient
both statements put together also don’t help so answer should be E on this However, the OA is different Want to have u r opinion guys. Can u please tell me where I am wrong on this? Clearly, x+y will always be greater than z x+z can also be greater than y, and y and z will also always be greater than x either way, with these 3 facts, we can already answer the question



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Re: DS question [#permalink]
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08 Aug 2008, 04:06
here from option B we can say x+y>z. but there is a difference betn saying a)x+y>z and b) only x+y>z



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Re: DS question [#permalink]
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08 Aug 2008, 07:23
vdhawan1 wrote: Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a triangle
statement 1 is clearly not sufficient from statement 2 it can follow that x+y>z but it can equally follow that z+y>x hence insufficient
both statements put together also don’t help so answer should be E on this However, the OA is different Want to have u r opinion guys. Can u please tell me where I am wrong on this? Clear B... Question Asked.. is x+y>z?... answer is yes.. then B is suffcient..
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Re: DS question [#permalink]
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08 Aug 2008, 21:00
vdhawan1 wrote: Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a triangle
statement 1 is clearly not sufficient from statement 2 it can follow that x+y>z but it can equally follow that z+y>x hence insufficient
both statements put together also don’t help so answer should be E on this However, the OA is different Want to have u r opinion guys. Can u please tell me where I am wrong on this? IMO B (1) is in insuffi > x^2+y^2 = (x+y)^22xy (x+y)^22xyz^2>0 => x,y signs and values matter here in boh the cases when z<x+y or z>x+y (2) is sufficient since properties of triangle sum of two sides is greater than the third sideIMO B
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Re: DS question [#permalink]
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08 Aug 2008, 23:28
vdhawan1 wrote: Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a triangle
statement 1 is clearly not sufficient from statement 2 it can follow that x+y>z but it can equally follow that z+y>x hence insufficient
both statements put together also don’t help so answer should be E on this However, the OA is different Want to have u r opinion guys. Can u please tell me where I am wrong on this? IMO B) Statement 1) conflicts when you change from +ve to ve Statement 2) is perfect










