Is x+yz (1) (x^2+y^2)z^2 (2) x, y, z are sides of a

Question

Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle

statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help 
so answer should be E on this 
However, the OA is different 
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

alpha_plus_gamma · Answer

IMHO, it should be B

If its sure that x+y>z , and question is asking the same, why to bother if z+y>x or not?

gmat2ndtime · Answer

B .... sum of the two sides of a triangle is greater than the third side.

vd · Answer

See my point is that yes surely x+y>z is inferable, but equally infereable is z+y>x , then why not that option 
the idea is that this option brings in two different possibilities, and hence the option is insufficent to answer the question.

therefore this statement is insufficent.

so shdnt the answer be E on this

Can some more guys give thier opinion on this

Thanks

aaron22197 · Answer

I think all x+y>z has to be true if x,y,z are the sides of the triangle. I agree that y+z>x and z+y>x are also true. But the question stem specifically asks for x+y. Hence B. what's the OA on this?

bsd_lover · Answer

You're right 
z+y > x and also x+z > y and finally x+y > z if they are three sides of a triangle.

Hence B is sufficient.

ritula · Answer

The answer is definitely B. 
See take it this way.
let the three sides of triangle be x,y and z respectively
x+y>z
x+z>y
y+z>x
All three conditions are true.
We are asked abt 1 of them which ios definitely true. so it should be B only

redbeanaddict · Answer

Clearly, x+y will always be greater than z
x+z can also be greater than y, and y and z will also always be greater than x
either way, with these 3 facts, we can already answer the question

arjtryarjtry · Answer

here from option B we can say x+y>z. but there is a difference betn saying
a)x+y>z and
b) only x+y>z

x2suresh · Answer

Clear B...

Question Asked.. is x+y>z?... answer is yes.. then B is suffcient..

spriya · Answer

IMO B 
(1) is in insuffi -> 
x^2+y^2 = (x+y)^2-2xy 
(x+y)^2-2xy-z^2>0 => x,y signs and values matter here in boh the cases when z<x+y or z>x+y

(2) is sufficient since properties of triangle

sum of two sides is greater than the third side 
IMO B

nmohindru · Answer

IMO B)

Statement 1) conflicts when you change from +ve to -ve

Statement 2) is perfect

Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a

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