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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a

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Is x+y>z (1) (x^2+y^2)>z^2 (2) x, y, z are sides of a [#permalink]

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New post 19 Jun 2008, 04:50
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Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?
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Director
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Re: DS question [#permalink]

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New post 19 Jun 2008, 06:29
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?


IMHO, it should be B

If its sure that x+y>z , and question is asking the same, why to bother if z+y>x or not?

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Re: DS question [#permalink]

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New post 19 Jun 2008, 06:34
B .... sum of the two sides of a triangle is greater than the third side.

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Re: DS question [#permalink]

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New post 19 Jun 2008, 23:12
alpha_plus_gamma wrote:
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?


IMHO, it should be B

If its sure that x+y>z , and question is asking the same, why to bother if z+y>x or not?


See my point is that yes surely x+y>z is inferable, but equally infereable is z+y>x , then why not that option
the idea is that this option brings in two different possibilities, and hence the option is insufficent to answer the question.

therefore this statement is insufficent.

so shdnt the answer be E on this

Can some more guys give thier opinion on this

Thanks
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Manager
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Re: DS question [#permalink]

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New post 19 Jun 2008, 23:33
I think all x+y>z has to be true if x,y,z are the sides of the triangle. I agree that y+z>x and z+y>x are also true. But the question stem specifically asks for x+y. Hence B. what's the OA on this?

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Re: DS question [#permalink]

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New post 20 Jun 2008, 03:58
You're right
z+y > x and also x+z > y and finally x+y > z if they are three sides of a triangle.

Hence B is sufficient.

vdhawan1 wrote:
See my point is that yes surely x+y>z is inferable, but equally infereable is z+y>x , then why not that option
the idea is that this option brings in two different possibilities, and hence the option is insufficent to answer the question.

therefore this statement is insufficent.

so shdnt the answer be E on this

Can some more guys give thier opinion on this

Thanks

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Re: DS question [#permalink]

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New post 20 Jun 2008, 04:08
The answer is definitely B.
See take it this way.
let the three sides of triangle be x,y and z respectively
x+y>z
x+z>y
y+z>x
All three conditions are true.
We are asked abt 1 of them which ios definitely true. so it should be B only

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Manager
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Re: DS question [#permalink]

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New post 21 Jun 2008, 07:21
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?

Clearly, x+y will always be greater than z
x+z can also be greater than y, and y and z will also always be greater than x
either way, with these 3 facts, we can already answer the question

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Re: DS question [#permalink]

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New post 08 Aug 2008, 04:06
here from option B we can say x+y>z. but there is a difference betn saying
a)x+y>z and
b) only x+y>z

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Re: DS question [#permalink]

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New post 08 Aug 2008, 07:23
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?


Clear B...

Question Asked.. is x+y>z?... answer is yes.. then B is suffcient..
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Re: DS question [#permalink]

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New post 08 Aug 2008, 21:00
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?


IMO B
(1) is in insuffi ->
x^2+y^2 = (x+y)^2-2xy
(x+y)^2-2xy-z^2>0 => x,y signs and values matter here in boh the cases when z<x+y or z>x+y

(2) is sufficient since properties of triangle

sum of two sides is greater than the third side
IMO B
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Re: DS question [#permalink]

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New post 08 Aug 2008, 23:28
vdhawan1 wrote:
Is x+y>z
(1) (x^2+y^2)>z^2
(2) x, y, z are sides of a triangle



statement 1 is clearly not sufficient
from statement 2 it can follow that x+y>z but it can equally follow that z+y>x
hence insufficient

both statements put together also don’t help
so answer should be E on this
However, the OA is different
Want to have u r opinion guys. Can u please tell me where I am wrong on this?


IMO B)

Statement 1) conflicts when you change from +ve to -ve

Statement 2) is perfect

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Re: DS question   [#permalink] 08 Aug 2008, 23:28
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