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Is |x| = y - z ? 1. x + y = z 2. x < 0 28 Jan 2009, 08:23
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Is |x| = y - z ?

1. x + y = z
2. x < 0



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Is |x| = y - z ? 1. x + y = z 2. x < 0 28 Jan 2009, 09:02
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IMO A.

Stmt 1 - X + Y = Z ==> X = Z - Y or -X = Y - Z ==> |X| = Y-Z. Sufficient.

Stmt 2 - X < 0 but no information related to Y & Z. Insufficient.
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Is |x| = y - z ? 1. x + y = z 2. x < 0 28 Jan 2009, 10:54
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I think, answer should be C.

if x = 2, y = 3 and z = 5, then
from stmt1: 2 + 3 = 5.
Also, |x| = 2
and y - z = -2
Hence, |x| does not equal y - z

Similarly, if x = -2. y = -3 and z = -5
then |x| = 2
y - z = 2

And |x| = y-z.

Thus, in order for|x| = y-z to be true, both statements are required. Hence, C should be the answer.
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Is |x| = y - z ? 1. x + y = z 2. x < 0 28 Jan 2009, 10:58
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scthakur
I think, answer should be C.

if x = 2, y = 3 and z = 5, then
from stmt1: 2 + 3 = 5.
Also, |x| = 2
and y - z = -2
Hence, |x| does not equal y - z

Similarly, if x = -2. y = -3 and z = -5
then |x| = 2
y - z = 2

And |x| = y-z.

Thus, in order for|x| = y-z to be true, both statements are required. Hence, C should be the answer.
Show more

OOPS!! missed -ve part.
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Is |x| = y - z ? 1. x + y = z 2. x < 0 28 Jan 2009, 12:14
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scthakur
I think, answer should be C.

if x = 2, y = 3 and z = 5, then
from stmt1: 2 + 3 = 5.
Also, |x| = 2
and y - z = -2
Hence, |x| does not equal y - z

Similarly, if x = -2. y = -3 and z = -5
then |x| = 2
y - z = 2

And |x| = y-z.

Thus, in order for|x| = y-z to be true, both statements are required. Hence, C should be the answer.
Show more


My weak point in Quant is always DS and in specific it worst when they are related to Absolute values / Inequalities.

Can one of you please explain why my approach is wrong.

Stmt 1 - X + Y = Z ==> X = Z - Y or -X = Y - Z ==> |X| = Y-Z. Sufficient.

Stmt 2 - X < 0 but no information related to Y & Z. Insufficient.

I know we can solve the DS questions by picking the numbers intelligently. But I am not able to rely on that process 100 %. So looking for alternate approaches on tackling DS questions. :cry:
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Is |x| = y - z ? 1. x + y = z 2. x < 0 28 Jan 2009, 13:09
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mrsmarthi
scthakur
I think, answer should be C.

if x = 2, y = 3 and z = 5, then
from stmt1: 2 + 3 = 5.
Also, |x| = 2
and y - z = -2
Hence, |x| does not equal y - z

Similarly, if x = -2. y = -3 and z = -5
then |x| = 2
y - z = 2

And |x| = y-z.

Thus, in order for|x| = y-z to be true, both statements are required. Hence, C should be the answer.


My weak point in Quant is always DS and in specific it worst when they are related to Absolute values / Inequalities.

Can one of you please explain why my approach is wrong.

Stmt 1 - X + Y = Z ==> X = Z - Y or -X = Y - Z ==> |X| = Y-Z. Sufficient.

Stmt 2 - X < 0 but no information related to Y & Z. Insufficient.

I know we can solve the DS questions by picking the numbers intelligently. But I am not able to rely on that process 100 %. So looking for alternate approaches on tackling DS questions. :cry:
Show more



statemet 1:
-X = Y - Z -->
we don't the whether X is +ve or -ve
assume X +ve then X= -Y+Z --> |X|=Z-Y ( answer No)
when x is -ve then -X= Y-Z --> |X|=Y-Z (answer Yes)
so not suffcieint

combine wiht stat2: X<0
it is suffcient.
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Is |x| = y - z ? 1. x + y = z 2. x < 0 28 Jan 2009, 23:28
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x2suresh
mrsmarthi
scthakur
I think, answer should be C.

if x = 2, y = 3 and z = 5, then
from stmt1: 2 + 3 = 5.
Also, |x| = 2
and y - z = -2
Hence, |x| does not equal y - z

Similarly, if x = -2. y = -3 and z = -5
then |x| = 2
y - z = 2

And |x| = y-z.

Thus, in order for|x| = y-z to be true, both statements are required. Hence, C should be the answer.


My weak point in Quant is always DS and in specific it worst when they are related to Absolute values / Inequalities.

Can one of you please explain why my approach is wrong.

Stmt 1 - X + Y = Z ==> X = Z - Y or -X = Y - Z ==> |X| = Y-Z. Sufficient.

Stmt 2 - X < 0 but no information related to Y & Z. Insufficient.

I know we can solve the DS questions by picking the numbers intelligently. But I am not able to rely on that process 100 %. So looking for alternate approaches on tackling DS questions. :cry:



statemet 1:
-X = Y - Z -->
we don't the whether X is +ve or -ve
assume X +ve then X= -Y+Z --> |X|=Z-Y ( answer No)
when x is -ve then -X= Y-Z --> |X|=Y-Z (answer Yes)
so not suffcieint

combine wiht stat2: X<0
it is suffcient.
Show more

Just keep in mind that with absolute values you are usually going to deal with 2 values (+/-)
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Is |x| = y - z ? 1. x + y = z 2. x < 0 29 Jan 2009, 03:09
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mrsmarthi
My weak point in Quant is always DS and in specific it worst when they are related to Absolute values / Inequalities.

Can one of you please explain why my approach is wrong.

Stmt 1 - X + Y = Z ==> X = Z - Y or -X = Y - Z ==> |X| = Y-Z. Sufficient.

Stmt 2 - X < 0 but no information related to Y & Z. Insufficient.

I know we can solve the DS questions by picking the numbers intelligently. But I am not able to rely on that process 100 %. So looking for alternate approaches on tackling DS questions. :cry:
Show more


What you are missing in the statement highlighted in red is that you are putting the left side in mod but not the right side. If I follow your steps then
|-x| = |y-z|
or, |x| = |y-z|

That is why stmt1 by itself is not sufficient.
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mrsmarthi
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Is |x| = y - z ? 1. x + y = z 2. x < 0 29 Jan 2009, 15:38
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scthakur
mrsmarthi
My weak point in Quant is always DS and in specific it worst when they are related to Absolute values / Inequalities.

Can one of you please explain why my approach is wrong.

Stmt 1 - X + Y = Z ==> X = Z - Y or -X = Y - Z ==> |X| = Y-Z. Sufficient.

Stmt 2 - X < 0 but no information related to Y & Z. Insufficient.

I know we can solve the DS questions by picking the numbers intelligently. But I am not able to rely on that process 100 %. So looking for alternate approaches on tackling DS questions. :cry:


What you are missing in the statement highlighted in red is that you are putting the left side in mod but not the right side. If I follow your steps then
|-x| = |y-z|
or, |x| = |y-z|

That is why stmt1 by itself is not sufficient.
Show more

yep true.....I missed that. Now I got it. Thank you.



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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