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nehapahuja29
Is xy > 0?

(1) |3 - x| < x + 5
(2) |2 - 2y| < y - 1

Good question!

S1: Because of how absolute values works, we have to solve for two equations: 3-x<x+5 and 3-x>x+5. We get x>-1 OR x<-1 as solutions. So x could be any number except -1. We are told nothing about y, so this is clearly insufficient.

S2: Again, we have two equations: 2-2y>y-1 and 2-2y<y-1. We get y>1 OR y<1 as solutions, so y could be any number except 1. We are told nothing about x, so this is clearly insufficient.

S1+S2: Based on the possible values of x and y, the product could be any number, positive, negative, or 0. We cannot determine whether xy>0, so the answer is E.
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nehapahuja29
Is xy > 0?

(1) |3 - x| < x + 5
(2) |2 - 2y| < y - 1


Dear GMATGuruNY

Can you please help with statement 2?

The left side is zero or positive and hence the right hand side must be positive .....then y-1> 0 ...y>1.......There is no number positive number that make inequality true

I tried to find solution but there is no solution at all. I got y >1 and y <1

is that allowable in GMAT test?
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nehapahuja29
Is xy > 0?

(1) |3 - x| < x + 5
(2) |2 - 2y| < y - 1


Dear GMATGuruNY

Can you please help with statement 2?

The left side is zero or positive and hence the right hand side must be positive .....then y-1> 0 ...y>1.......There is no number positive number that make inequality true

I tried to find solution but there is no solution at all. I got y >1 and y <1

is that allowable in GMAT test?

As you have discovered, there is no solution for Statement 2.

Statement 2: |2 - 2y| < y - 1
Since an absolute value cannot be less than 0, the right side of this inequality must be positive:
y-1 > 0
y > 1
For all values greater than 1, |2-2y| = 2y-2
Substituting |2-2y|= 2y-2 into |2-2y| < y-1, we get:
2y-2 < y-1
y < 1
Since Statement 2 is valid only for values greater than 1, the resulting inequality in red is not possible.
Implication:
Statement 2 has no valid solutions.

The problem is flawed.
To my knowledge, no official problem has included a statement for which there is no solution.
I would disregard this problem.
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nehapahuja29
Is xy > 0?

(1) |3 - x| < x + 5
(2) |2 - 2y| < y - 1


Dear GMATGuruNY

Can you please help with statement 2?

The left side is zero or positive and hence the right hand side must be positive .....then y-1> 0 ...y>1.......There is no number positive number that make inequality true

I tried to find solution but there is no solution at all. I got y >1 and y <1

is that allowable in GMAT test?

As you have discovered, there is no solution for Statement 2.

Statement 2: |2 - 2y| < y - 1
Since an absolute value cannot be less than 0, the right side of this inequality must be positive:
y-1 > 0
y > 1
For all values greater than 1, |2-2y| = 2y-2
Substituting |2-2y|= 2y-2 into |2-2y| < y-1, we get:
2y-2 < y-1
y < 1
Since Statement 2 is valid only for values greater than 1, the resulting inequality in red is not possible.
Implication:
Statement 2 has no valid solutions.

The problem is flawed.
To my knowledge, no official problem has included a statement for which there is no solution.
I would disregard this problem.

Thanks a lo for your support
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nehapahuja29
Is xy > 0?

(1) |3 - x| < x + 5
(2) |2 - 2y| < y - 1

Good question!

S1: Because of how absolute values works, we have to solve for two equations: 3-x<x+5 and 3-x>x+5. We get x>-1 OR x<-1 as solutions. So x could be any number except -1. We are told nothing about y, so this is clearly insufficient.

S2: Again, we have two equations: 2-2y>y-1 and 2-2y<y-1. We get y>1 OR y<1 as solutions, so y could be any number except 1. We are told nothing about x, so this is clearly insufficient.

S1+S2: Based on the possible values of x and y, the product could be any number, positive, negative, or 0. We cannot determine whether xy>0, so the answer is E.


WRONG, Bad question. Statement (2) is not true for any value of Y; therefore, this question is flawed.
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Chitnis3
Is xy > 0?

(1) |3 - x| < x + 5
(2) |2 - 2y| < y - 1

Considering statement (1)
|3 - x| < x + 5

For x<-5, statement (1) will be false.
For -5<x<3, statement (1) will be true.
For x>3, statement (1) again will be false.

So statement (1) is only valid for x between -5 & 3.

Not sure if xy>0, Hence option A & D are eliminated

Considering statement (2)
|2 - 2y| < y - 1
This statement can never be true.
Option B is eliminated

Combining we're still not able to find if xy>0.
Hence, Option E is the correct answer


Check your answer to statement one.
For -5<x<3, statement (1) will be true. WRONG.
Try x = -4 NOT TRUE
Try x= 4 TRUE
The answer to statement 1 is x > -1

As for statement (2), you are right, it can never be true. So this is an incorrect GMAT question. All statements must be true.
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