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Bunuel
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chetan2u
Is xy > 0?

Do x and y have same sign?


(1) \(x - y = 2\)
x=4, y=2, answer is yes.
x=2, y=0, answer is no.


(2) \(\frac{x}{y}<1\)
If \(0<\frac{x}{y}<1\), answer is yes.
If \(\frac{x}{y}<0\), answer is no.


Combined
If x=1, y=-1, answer is no.
If x=-2, y=-4, answer is yes.
Insufficient


E
But by combining the 2 statements we have statements, x-y = 2 & x<y.
And your combined case states x>y (If x=1, y=-1, answer is no), which is incorrect.

If x<y, then either x & y both will be +ve or both will be -ve, i which case we have a sufficient answer to the question.

So I think correct answer is C.

Why should x<y????

x/y<1….1/(-1)=-1<1…..fits in statement II
x-y=2….1-(-1)=2…..fits in statement I
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Bunuel
Is xy > 0?


(1) \(x - y = 2\)
y=-2 and x=0 no
y=2 , x=4 , yes

Clearly insufficient

(2) \(\frac{x}{y}<1\)
x=1, y=-1 , no
x=2 , y=4 , yes

when 1 and 2 is combined
If x=1, y=-1, no
If x=-2, y=-4, yes

Therefore IMO E
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