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Bunuel
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Is xy <= 6 ? (1) 1 <= x <= 2 and 4 <= y <= 6 (2) x + y = 7 16 Dec 2017, 01:46
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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35% (medium)

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70% (01:40) correct 30% (01:36) wrong based on 70 sessions

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Is \(xy \leq 6\) ?

(1) \(1 \leq x \leq 2\) and \(4 \leq y \leq 6\)
(2) x + y = 7
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E
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exc4libur
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Is xy <= 6 ? (1) 1 <= x <= 2 and 4 <= y <= 6 (2) x + y = 7 Updated on: 18 Dec 2017, 03:05
Originally posted by exc4libur on 16 Dec 2017, 09:56.
Last edited by exc4libur on 18 Dec 2017, 03:05, edited 2 times in total.
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Bunuel
Is \(xy \leq 6\) ?

(1) \(1 \leq x \leq 2\) and \(4 \leq y \leq 6\)
(2) x + y = 7
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Is \(xy \leq 6\)? If x and y are opposite signs, then xy is ≤ 6; If they are the same sign, then we must solve for x and y.

(1) \(1 \leq x \leq 2\) and \(4 \leq y \leq 6\). If we multiply both inequalities we have: \(4 \leq xy \leq 12\), then xy could be ≥ 6 or xy ≤ 6, insufficient.

(2) \(x + y = 7\). If x = 3 and y = 4, xy = 12, condition is false. If x = 1 and y = 6, xy = 6, condition is true. Both cases, x and y could be opposite signs or not.. insufficient.

(3) Combining both: (1) x and y are the same signs (positive) bound by the inequality, and (2) their sum has to be equal to 7.

So if x = 1 y = 6, x + y = 7 and xy = 6 ≤ 6. But if x = 2 y = 5, x + y = 7 then xy = 10 ≥ 6. We have more than one possibility, insufficient.

(E) is the answer.
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Is xy <= 6 ? (1) 1 <= x <= 2 and 4 <= y <= 6 (2) x + y = 7 16 Dec 2017, 12:08
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exc4libur
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Is \(xy \leq 6\) ?

(1) \(1 \leq x \leq 2\) and \(4 \leq y \leq 6\)
(2) x + y = 7

Is \(xy \leq 6\)? If x and y are opposite signs, then xy is ≤ 6; If they are the same sign, then we must solve for x and y.

(1) \(1 \leq x \leq 2\) and \(4 \leq y \leq 6\). If we multiply both inequalities we have: \(4 \leq xy \leq 12\), then xy could be ≥ 6 or xy ≤ 6, insufficient.

(2) \(x + y = 7\). If x = 3 and y = 4, xy = 12, condition is false. If x = 3 and y = -4, xy = -12, condition is true. Both cases, x and y could be opposite signs or not.. insufficient.

(3) Combining both: (1) x and y are the same signs (positive), and (2) their sum is equal to 7. There are only 2 solutions for x that meet the inequality: x = 1 or x = 2. And to meet the (2) statement, y has to be y = 6 or y = 5. Thus, xy is either (1)(6) = 6 or (2)(5) = 10, which both are ≥ 6, sufficient.

(C) is the answer.
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Hi exc4libur

highlighted portion is not correct. if x=3 & y =-4 then x+y=-1 which is not possible here. :-)
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Is xy <= 6 ? (1) 1 <= x <= 2 and 4 <= y <= 6 (2) x + y = 7 16 Dec 2017, 12:20
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Quote:
Hi exc4libur

highlighted portion is not correct. if x=3 & y =-4 then x+y=-1 which is not possible here. :-)
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Hi niks, thanks!! :) I got distracted, but its correct now. regds.
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Is xy <= 6 ? (1) 1 <= x <= 2 and 4 <= y <= 6 (2) x + y = 7 17 Dec 2017, 17:42
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exc4libur
Bunuel
Is \(xy \leq 6\) ?

(1) \(1 \leq x \leq 2\) and \(4 \leq y \leq 6\)
(2) x + y = 7

Is \(xy \leq 6\)? If x and y are opposite signs, then xy is ≤ 6; If they are the same sign, then we must solve for x and y.

(1) \(1 \leq x \leq 2\) and \(4 \leq y \leq 6\). If we multiply both inequalities we have: \(4 \leq xy \leq 12\), then xy could be ≥ 6 or xy ≤ 6, insufficient.

(2) \(x + y = 7\). If x = 3 and y = 4, xy = 12, condition is false. If x = 1 and y = 6, xy = 6, condition is true. Both cases, x and y could be opposite signs or not.. insufficient.

(3) Combining both: (1) x and y are the same signs (positive), and (2) their sum is equal to 7. There are only 2 solutions for x that meet the inequality: x = 1 or x = 2. And to meet the (2) statement, y has to be y = 6 or y = 5. Thus, xy is either (1)(6) = 6 or (2)(5) = 10, which both are ≥ 6, sufficient.

(C) is the answer.
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Hi,

Based on what you have provided, the answer should be E.

x =1 & y = 6.........xy ≤ 6.............Answer is Yes

x =2 & y = 5.........xy ≤ 10.............Answer is NO

Also small comment. The highlighted is not correct. You assumed that x and y are integers but x could be 1.9 & y could be 5.1. Nothing in the questions says that those are integers.
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Is xy <= 6 ? (1) 1 <= x <= 2 and 4 <= y <= 6 (2) x + y = 7 17 Dec 2017, 20:30
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The question is, Is xy<= 6? Hence, (1)(6) = 6 is a YES and (2)(5) = 10 is a NO. Answer should be E.
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Is xy <= 6 ? (1) 1 <= x <= 2 and 4 <= y <= 6 (2) x + y = 7 18 Dec 2017, 03:06
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Mo2men
exc4libur
Bunuel
Is \(xy \leq 6\) ?

(E) is the answer.
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Done, thank you Mo :)
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