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# Is y between 1 and 2, exclusive?

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Intern
Joined: 15 Dec 2015
Posts: 34
Is y between 1 and 2, exclusive?  [#permalink]

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25 Dec 2015, 18:32
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Difficulty:

65% (hard)

Question Stats:

54% (01:51) correct 46% (01:52) wrong based on 80 sessions

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Is y between 1 and 2, exclusive?

(1) y^2 is less than y

(2) y^2 + y is between 1 and 2, exclusive

Sent from my iPhone using Tapatalk
Math Expert
Joined: 02 Aug 2009
Posts: 7035
Re: Is y between 1 and 2, exclusive?  [#permalink]

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25 Dec 2015, 19:11
sara86 wrote:
Is y between 1 and 2, exclusive?

(1) y^2 is less than y

(2) y^2 + y is between 1 and 2, exclusive

Sent from my iPhone using Tapatalk

Hi,

(1) y^2 is less than y
since y^2 is less than y, we can say that y is positive..
Also any value above 1, will have a square more than number ... so y has to be between 0 and 1.... suff

(2) y^2 + y is between 1 and 2, exclusive..
any number more than 1 will have its square more than 1..
so when we add square of the number and the number itself (y^2 + y), it will always be more than 2..
so the answer to Q is NO.... suff
ans D
_________________

1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html

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Intern
Joined: 15 Dec 2015
Posts: 34
Re: Is y between 1 and 2, exclusive?  [#permalink]

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25 Dec 2015, 19:20
But statement (2) explicitly states the condition that (y^2 + y) is within the range 1 and 2, exclusive...

So how did statement (2) disprove the range given in the question ?

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Math Expert
Joined: 02 Aug 2009
Posts: 7035
Re: Is y between 1 and 2, exclusive?  [#permalink]

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25 Dec 2015, 19:29
sara86 wrote:
But statement (2) explicitly states the condition that (y^2 + y) is within the range 1 and 2, exclusive...

So how did statement (2) disprove the range given in the question ?

Sent from my iPhone using Tapatalk

Hi,
Any number above 1 will have the value y^2 + y more than 2...
this means if it is given as y^2+y lies between 1 and 2, y cannot be greater than 1..
this gives us an answer to the statement Is y between 1 and 2, exclusive as NO..
this makes 2 alone also suff..
As a matter of fact if it is given as y^2+y lies between 1 and 2, y will be between 0 and 1..
_________________

1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html

GMAT online Tutor

Intern
Joined: 15 Dec 2015
Posts: 34
Re: Is y between 1 and 2, exclusive?  [#permalink]

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25 Dec 2015, 19:41
Oh okay, now I get it , the question got my mind twisted, lol!

Thnx anyway!

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Director
Joined: 27 May 2012
Posts: 609
Re: Is y between 1 and 2, exclusive?  [#permalink]

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19 Jul 2018, 05:43
sara86 wrote:
Is y between 1 and 2, exclusive?

(1) y^2 is less than y

(2) y^2 + y is between 1 and 2, exclusive

Sent from my iPhone using Tapatalk

Although the answer is D . but both the statements are giving different values of y.
This will not happen in the GMAT.

Here for statement 1 : y is between 0 and 1
For statement 2: Y is NOT between 0 and 1 . Check by putting y = 1/2 in statement 2 and we will see that y^2 + y is 3/4 hence y is not between 1 and 2 .

In fact can anybody give me the the range of values of Y for which statement 2 is satisfied ? Thanks .
_________________

- Stne

Math Expert
Joined: 02 Aug 2009
Posts: 7035
Is y between 1 and 2, exclusive?  [#permalink]

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19 Jul 2018, 05:54
stne wrote:
sara86 wrote:
Is y between 1 and 2, exclusive?

(1) y^2 is less than y

(2) y^2 + y is between 1 and 2, exclusive

Sent from my iPhone using Tapatalk

Although the answer is D . but both the statements are giving different values of y.
This will not happen in the GMAT.

Here for statement 1 : y is between 0 and 1
For statement 2: Y is NOT between 0 and 1 . Check by putting y = 1/2 in statement 2 and we will see that y^2 + y is 3/4 hence y is not between 1 and 2 .

In fact can anybody give me the the range of values of Y for which statement 2 is satisfied ? Thanks .

$$y^2+y>1.......y(y+1)>1.......y>0..or..y<-1$$..
$$y^2+y<2.......y(y+1)<2........y<1...or....y<-2$$..
So range is 0<y<1 and y<-2
_________________

1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html

GMAT online Tutor

Director
Joined: 27 May 2012
Posts: 609
Re: Is y between 1 and 2, exclusive?  [#permalink]

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19 Jul 2018, 06:26
chetan2u wrote:
stne wrote:
sara86 wrote:
Is y between 1 and 2, exclusive?

(1) y^2 is less than y

(2) y^2 + y is between 1 and 2, exclusive

Sent from my iPhone using Tapatalk

Although the answer is D . but both the statements are giving different values of y.
This will not happen in the GMAT.

Here for statement 1 : y is between 0 and 1
For statement 2: Y is NOT between 0 and 1 . Check by putting y = 1/2 in statement 2 and we will see that y^2 + y is 3/4 hence y is not between 1 and 2 .

In fact can anybody give me the the range of values of Y for which statement 2 is satisfied ? Thanks .

$$y^2+y>1.......y(y+1)>1.......y>0..or..y<-1$$..
$$y^2+y<2.......y(y+1)<2........y<1...or....y<-2$$..
So range is 0<y<1 and y<-2

Thank you for your reply , if range is between 0 and 1( for statement 2) then when I put y = 1/2 in statement 2 , why don't I get y^2 + y is between 1 and 2 ? rather y^2 +y = 3/4 which is less than 1.
_________________

- Stne

Math Expert
Joined: 02 Aug 2009
Posts: 7035
Re: Is y between 1 and 2, exclusive?  [#permalink]

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19 Jul 2018, 06:41
1
stne wrote:
chetan2u wrote:
stne wrote:

Although the answer is D . but both the statements are giving different values of y.
This will not happen in the GMAT.

Here for statement 1 : y is between 0 and 1
For statement 2: Y is NOT between 0 and 1 . Check by putting y = 1/2 in statement 2 and we will see that y^2 + y is 3/4 hence y is not between 1 and 2 .

In fact can anybody give me the the range of values of Y for which statement 2 is satisfied ? Thanks .

$$y^2+y>1.......y(y+1)>1.......y>0..or..y<-1$$..
$$y^2+y<2.......y(y+1)<2........y<1...or....y<-2$$..
So range is 0<y<1 and y<-2

Thank you for your reply , if range is between 0 and 1( for statement 2) then when I put y = 1/2 in statement 2 , why don't I get y^2 + y is between 1 and 2 ? rather y^2 +y = 3/4 which is less than 1.

Hi...
I didnt get into exact calculation..

so $$y^2+y-1>0$$... let it be =0 then roots are $$\frac{-b+\sqrt{b^2-4ac}}{2}.......\frac{-1+\sqrt{5}}{2}=\frac{-1+2.236}{2}=1.236/2=0.618$$
so 0.618<y<1
_________________

1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html

GMAT online Tutor

Director
Joined: 27 May 2012
Posts: 609
Re: Is y between 1 and 2, exclusive?  [#permalink]

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19 Jul 2018, 07:03
Thank you again, shouldn't both the statements give the same range of Y, isn't there a contradiction , among the statements. Especially since the answer is D.

For statement 1 : 0 < Y<1
For statement 2 : 0.618<y<1
_________________

- Stne

Math Expert
Joined: 02 Aug 2009
Posts: 7035
Re: Is y between 1 and 2, exclusive?  [#permalink]

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19 Jul 2018, 07:13
stne wrote:
Thank you again, shouldn't both the statements give the same range of Y, isn't there a contradiction , among the statements. Especially since the answer is D.

For statement 1 : 0 < Y<1
For statement 2 : 0.618<y<1

It's Correct because the range 0.618<y<1 is subset of the range 0<y<1...
If we were to find the range then it will be 0.618 to 1..

What could be wrong is..
If we had 0<y<1 and second statement gave y>2
Here although Ans would be D, but question will be flawed as it gave two different ranges
_________________

1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html

GMAT online Tutor

Director
Joined: 27 May 2012
Posts: 609
Re: Is y between 1 and 2, exclusive?  [#permalink]

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19 Jul 2018, 08:29
chetan2u wrote:
stne wrote:
Thank you again, shouldn't both the statements give the same range of Y, isn't there a contradiction , among the statements. Especially since the answer is D.

For statement 1 : 0 < Y<1
For statement 2 : 0.618<y<1

It's Correct because the range 0.618<y<1 is subset of the range 0<y<1...
If we were to find the range then it will be 0.618 to 1..

What could be wrong is..
If we had 0<y<1 and second statement gave y>2
Here although Ans would be D, but question will be flawed as it gave two different ranges

Thank you, Got it.
_________________

- Stne

Re: Is y between 1 and 2, exclusive? &nbs [#permalink] 19 Jul 2018, 08:29
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