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12 Oct 2015, 13:27
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Please help!
Is Z even? If 3z is even.
As per my understanding yes, because if 3z is even then z has to be even. Because 3 * Even will only be hence, z should be even.
Is my thought process right?
Is Z even? If 3z is even.
As per my understanding yes, because if 3z is even then z has to be even. Because 3 * Even will only be hence, z should be even.
Is my thought process right?
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Updated on: 13 Oct 2015, 00:22
Originally posted by paulaalv11 on 12 Oct 2015, 14:21.
Last edited by paulaalv11 on 13 Oct 2015, 00:22, edited 1 time in total.
Last edited by paulaalv11 on 13 Oct 2015, 00:22, edited 1 time in total.
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Yes, absolutely right! Or if you prefer, think of the inverse: since odd*odd = odd, z cannot be odd, because 3z then would be odd, therefore z must be even.
***Please, note that this stands only if z is an integer***
Does this help?
Cheers!
***Please, note that this stands only if z is an integer***
Does this help?
Cheers!
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12 Oct 2015, 14:32
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deepaks12988
The poster above has neglected the case when z=2/3 which will give you an even number for 3z. If it is mentioned that z has to be an integer, then yes, z will be even if 3z is even but if it is not mentioned that z must be an integer then this statement will not be sufficient.
Hope this helps.
