nkmungila wrote:

Jack and Anne had coins in the ratio 3 : 4. Jack gave a few coins to Anne and the ratio became 1 : 4. What is the minimum

possible number of coins that Jack gave Anne?

A. 1

B. 3

C. 6

D. 7

E. 8

We can express the ratio of the number of Jack’s coins to the number of Anne’s coins as 3x : 4x. Let’s let n = the number of coins that Jack gave to Anne. Thus, Jack now has (3x - n) coins and Anne has (4x + n) coins, and this new ratio is 1 : 4, as shown in this equation:

(3x - n)/(4x + n) = 1/4

4(3x - n) = 4x + n

12x - 4n = 4x + n

8x = 5n

x = 5n/8

Since x is an integer and 8 does not divide 5, n must divide 8, and thus the minimum value for n is 8.

Answer: E

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