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arjtryarjtry
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arjtryarjtry
OA b

I got B the first time, however after a second look it looks like E.

What is the source of your Question and is there an official explanation since I cannot see the error in durgesh's or my answer.
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x97agarwal
Jack bought one shampoo, two toothpastes, and two toothbrushes. If the total cost is $13, and all items have an integer price, in dollars, what is the price for the toothbrush?

From the Q you will get the equation: S +2T + 2B = 13

S1. No item priced of $4.

See how may ways you can get 13 without pricing any item at $4
First way: 3+ 2(3)+ 2(2) = 3+6+4 = 13
Second way: 5 + 2(2) + 2(2) = 5+4+4 = 13
Third way: 5+ 2(1) + 2(3) = 5+2+6 = 13
7 +2(2) + 2(1) = 13
Hence Maybe case so AD are out

S2 A shampoo is more expensive than toothpaste, and toothpaste is more expensive than a toothbrush.
First way: 5 + 2(3) + 2(1) = 5+6+2 = 13 ; only one way to satisfy the eq
Second way 7 +2(2) + 2(1) = 13
Maybe so B is out

Combining you still get two values so IMO E


you ur self have got the ans as 1 for the brush in both 1) and 2) of stat 2
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arjtryarjtry
x97agarwal
Jack bought one shampoo, two toothpastes, and two toothbrushes. If the total cost is $13, and all items have an integer price, in dollars, what is the price for the toothbrush?

From the Q you will get the equation: S +2T + 2B = 13

S1. No item priced of $4.

See how may ways you can get 13 without pricing any item at $4
First way: 3+ 2(3)+ 2(2) = 3+6+4 = 13
Second way: 5 + 2(2) + 2(2) = 5+4+4 = 13
Third way: 5+ 2(1) + 2(3) = 5+2+6 = 13
7 +2(2) + 2(1) = 13
Hence Maybe case so AD are out

S2 A shampoo is more expensive than toothpaste, and toothpaste is more expensive than a toothbrush.
First way: 5 + 2(3) + 2(1) = 5+6+2 = 13 ; only one way to satisfy the eq
Second way 7 +2(2) + 2(1) = 13
Maybe so B is out

Combining you still get two values so IMO E


you ur self have got the ans as 1 for the brush in both 1) and 2) of stat 2

Thanks, overlooked it. I am trying to do multiple things at once.



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