SidR wrote:

Jake and Ryan worked together on a job for which they were each paid a dollars in advance. If Jake spent 20% more time working on the job than Ryan did, and Ryan gave Jake b dollars, so that their hourly wages were equal, then, in terms of b, how much was Jake paid in advance?

(A) 0.8b

(B) 1.1b

(C) 1.2b

(D) 10b

(E) 11b

Please help with the shortest approach.

The shortest approach will be to assume the # of hours of work required.

Lets assume the job required 10 hours of work for a pay of X dollar.

So Ryan worked for 10 hours for X dollars.

& Jake worked for 20% more time than Ryan, hence Jake worked for 12 hours for X dollars.

Now Ryan gave Jake "b" dollars, which made their hourly pay equal.

So, we get (X-b)/10 = (X+b)/12

Solving it for X we get X = 11b.

Answer E.

Thanks,

GyM

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