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22 Apr 2015, 08:37
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
49% (01:16) correct
51%
(01:20)
wrong
based on 251
sessions
History
Date
Time
Result
Not Attempted Yet
Joey is planning to throw a small party and for that he needs to do the following tasks:
I. Decide guest list
II. Send invites
III. Arrange catering
IV. Decide the venue
V. Rent a music system
The tasks can be done in any order as long as the invites are sent after the guest list is decided. In how many ways can Joey do the five tasks listed above?
I. Decide guest list
II. Send invites
III. Arrange catering
IV. Decide the venue
V. Rent a music system
The tasks can be done in any order as long as the invites are sent after the guest list is decided. In how many ways can Joey do the five tasks listed above?
- A. 24
B. 48
C. 60
D. 120
E. 240
22 Apr 2015, 09:13
Kudos
Bookmarks
PrepTap
Joey is planning to throw a small party and for that he needs to do the following tasks:
I. Decide guest list
II. Send invites
III. Arrange catering
IV. Decide the venue
V. Rent a music system
The tasks can be done in any order as long as the invites are sent after the guest list is decided. In how many ways can Joey do the five tasks listed above?
I. Decide guest list
II. Send invites
III. Arrange catering
IV. Decide the venue
V. Rent a music system
The tasks can be done in any order as long as the invites are sent after the guest list is decided. In how many ways can Joey do the five tasks listed above?
- A. 24
B. 48
C. 60
D. 120
E. 240
These 5 tasks can be arranged in 5! = 120 ways. In half of them invites are sent after the guest list is decided and in half of them before. So, there are total of 120/2 = 60 ways to arrange the task so that the invites are sent after the guest list is decided.
Answer: C.
Questions about the same concept to practice:
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meg-and-bob-are-among-the-5-participants-in-a-cycling-race-58095.html
in-how-many-different-ways-can-the-letters-a-a-b-91460.html
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Hope it helps.
28 Nov 2017, 13:57
Kudos
Bookmarks
Hi All,
We're told that there are 5 tasks to be completed. IF there were no 'restrictions', then there would be 5! = (5)(4)(3)(2)(1) = 120 different possible 'orders' for those 5 tasks. However, there IS a 'restriction' - the invites can only be sent AFTER the guest list is determined. In the original 120 possible orders, the 5 tasks are done one-at-a-time, so HALF of the options had the invites sent BEFORE the guest list and HALF of the options had the invites sent AFTER the guest list. Thus, there are (1/2)(120) = 60 possible orders in which the invites are sent after the guest list.
Final Answer:
GMAT assassins aren't born, they're made,
Rich
We're told that there are 5 tasks to be completed. IF there were no 'restrictions', then there would be 5! = (5)(4)(3)(2)(1) = 120 different possible 'orders' for those 5 tasks. However, there IS a 'restriction' - the invites can only be sent AFTER the guest list is determined. In the original 120 possible orders, the 5 tasks are done one-at-a-time, so HALF of the options had the invites sent BEFORE the guest list and HALF of the options had the invites sent AFTER the guest list. Thus, there are (1/2)(120) = 60 possible orders in which the invites are sent after the guest list.
Final Answer:
GMAT assassins aren't born, they're made,
Rich
