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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6
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15 Apr 2012, 21:16
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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ? A. 360 B. 120 C. 80 D. 240 E. 60
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6
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16 Apr 2012, 00:58
gmihir wrote: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?
A. 360 B. 120 C. 80 D. 240 E. 60 Total # of arrangement of 6 people is 6!. In half of the cases Susan will be seated left to Tim and in half of the cases Susan will be seated right to Tim (why should one seating arrangement have more ways to occur than another?). So, # of arrangements to satisfy the given condition is 6!/2=360. Answer: A. Similar questions to practice: inhowmanydifferentwayscanthelettersaab91460.htmlsixmobstershavearrivedatthetheaterforthepremiereofthe126151.htmlHope it helps.
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6
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12 Apr 2014, 01:19
satsymbol wrote: Why Can not I use Glue method here? SK together, with 4 others  5! = 120 ways. Hi, When you are using the above method what you are assuming is that they are sitting next to each other always, which is not what the question states. The question only says that S is always sitting left of T, maybe next, maybe away 1 chair ...there is no constraint on that.  Kudos, if the post helped




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15 Apr 2012, 22:57
Total number of arrangements = 6! = 720 In exactly half, Susan will be to the left of Tim, which gives us 360 arrangements Option (A)
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6
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11 Apr 2014, 19:47
Why Can not I use Glue method here? SK together, with 4 others  5! = 120 ways.



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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6
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12 Apr 2014, 19:27
ind23 wrote: satsymbol wrote: Why Can not I use Glue method here? SK together, with 4 others  5! = 120 ways. Hi, When you are using the above method what you are assuming is that they are sitting next to each other always, which is not what the question states. The question only says that S is always sitting left of T, maybe next, maybe away 1 chair ...there is no constraint on that.  Kudos, if the post helpedgot it.. where i was failing... thanks..



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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6
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12 Apr 2014, 21:33
No problem:) Do press +1 Kudos if it helped.
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6
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24 Jun 2015, 03:37
Bunuel wrote: gmihir wrote: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?
A. 360 B. 120 C. 80 D. 240 E. 60 Total # of arrangement of 6 people is 6!. In half of the cases Susan will be seated left to Tim and in half of the cases Susan will be seated right to Tim (why should one seating arrangement have more ways to occur than another?). So, # of arrangements to satisfy the given condition is 6!/2=360. Answer: A. Similar questions to practice: inhowmanydifferentwayscanthelettersaab91460.htmlsixmobstershavearrivedatthetheaterforthepremiereofthe126151.htmlHope it helps. Hi Bunuel Could you confirm my thoughts? If the question asked that Susan should always sit DIRECTLY left to TIM, then the total # of arrangements would be: 5! = 120 ? Because you can "glue" Kim and Susan "together". But you still have 6 chairs, how would you account for that? Further: anyone also understod this part "Susan is seated always left to Tim" in the way that Susan needs to be seated directly left to Tim? Thanks



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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6
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24 Jun 2015, 21:53
gmihir wrote: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?
A. 360 B. 120 C. 80 D. 240 E. 60 This post discusses the symmetry concept and this question: http://www.veritasprep.com/blog/2011/10 ... spartii/
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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6
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25 Jun 2017, 10:58
reto wrote: Bunuel wrote: gmihir wrote: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?
A. 360 B. 120 C. 80 D. 240 E. 60 Total # of arrangement of 6 people is 6!. In half of the cases Susan will be seated left to Tim and in half of the cases Susan will be seated right to Tim (why should one seating arrangement have more ways to occur than another?). So, # of arrangements to satisfy the given condition is 6!/2=360. Answer: A. Similar questions to practice: http://gmatclub.com/forum/inhowmanyd ... 91460.htmlhttp://gmatclub.com/forum/sixmobsters ... 26151.htmlHope it helps. Hi Bunuel Could you confirm my thoughts? If the question asked that Susan should always sit DIRECTLY left to TIM, then the total # of arrangements would be: 5! = 120 ? Because you can "glue" Kim and Susan "together". But you still have 6 chairs, how would you account for that? Further: anyone also understod this part "Susan is seated always left to Tim" in the way that Susan needs to be seated directly left to Tim? Thanks Hi reto, The highlighted portion says that susan is sitting left to Tim, it doesn't necessarily mean next to him BUT always left to him. i.e. 1 way is S,T,_,_,_,_,_, next S,_,T,_,_,_,_ and so on. Hope this clears.



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Re: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6
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02 Jun 2019, 03:41
gmihir wrote: Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?
A. 360 B. 120 C. 80 D. 240 E. 60 for such cases arrangement would be such that ST are together and times when they are not together total ways 6! /2 = 360 IMO A



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Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6
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24 Nov 2019, 07:07
Bunuel, Hi hope you are doing well. Needed your guidance on this as i am not able to grasp the depth of the answer. With all due respect, Why dont we solve this by 5!? considering the two are inseparable...so making them as 1 and then calculating the arrangements.. I mean whats wrong in my technique is what I am trying to ask.




Susan, John, Daisy, Tim, Matt and Kim need to be seated in 6
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24 Nov 2019, 07:07






