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john and marcia bought a number of chairs at an auction.the

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john and marcia bought a number of chairs at an auction.the [#permalink]

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New post 18 Aug 2008, 20:29
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john and marcia bought a number of chairs at an auction.the average price of the chairs that marcia purchased was $50 and the average price of the chairs that josh purchased was $62. If the average price of all the chairs purchased was $53, what was the ratio of the number of chairs purchased by marcia to the number purchased by josh?

a. 1:1

b.1:2

c. 1:3

d. 3:1

e. 2:1

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New post 18 Aug 2008, 21:32
pattydread wrote:
john and marcia bought a number of chairs at an auction.the average price of the chairs that marcia purchased was $50 and the average price of the chairs that josh purchased was $62. If the average price of all the chairs purchased was $53, what was the ratio of the number of chairs purchased by marcia to the number purchased by josh?

a. 1:1

b.1:2

c. 1:3

d. 3:1

e. 2:1


Guessing Approach:M-$50 J - $62
Average - $53.
$53 is very near to Marcia so No of purchases are more for "Marcia" than "Josh"
A,B,C ---OUT
between D and E

50 is 3 points away from 53
62 is 9 points away from 53
1/3: 1/9 --> 3:1
D remains

Solving Approach:
x -- fraction of Marcia share
1-x -- fraction of Josh share

0 * x + (1-x)*12=3
x=3/4

Marcia/Josh ratio: 3/4 : 1/4 = 3:1
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New post 19 Aug 2008, 02:56
pattydread wrote:
john and marcia bought a number of chairs at an auction.the average price of the chairs that marcia purchased was $50 and the average price of the chairs that josh purchased was $62. If the average price of all the chairs purchased was $53, what was the ratio of the number of chairs purchased by marcia to the number purchased by josh?

a. 1:1

b.1:2

c. 1:3

d. 3:1

e. 2:1


There is faster way to address such Qs specially when you are running out of time.

Ratio will be = (62-50) - (53 - 50) / (62 - 50) - (62 - 53) = 9 / 3 = 3:1

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Re: ratios   [#permalink] 19 Aug 2008, 02:56
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john and marcia bought a number of chairs at an auction.the

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