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John can eat x doughnuts in y minutes. If Chen can eat doughnuts three

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John can eat x doughnuts in y minutes. If Chen can eat doughnuts three  [#permalink]

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New post 28 Mar 2016, 01:19
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A
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Difficulty:

  55% (hard)

Question Stats:

65% (02:20) correct 35% (02:24) wrong based on 111 sessions

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John can eat x doughnuts in y minutes. If Chen can eat doughnuts three times as fast as John, how many doughnuts will John and Chen eat in an hour?

A) \(15 (\frac{4x}{4})\)
B) \(60(\frac{3x}{y})\)
C) \(15(\frac{16x}{y})\)
D) \(60(\frac{x}{y})\)
E) \(60(\frac{x}{3y})\)

Preferably detailed algebraic solution please.
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Joined: 02 Aug 2009
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Re: John can eat x doughnuts in y minutes. If Chen can eat doughnuts three  [#permalink]

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New post 28 Mar 2016, 05:37
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kalita wrote:
John can eat x doughnuts in y minutes. If Chen can eat doughnuts three times as fast as John, how many doughnuts will John and Chen eat in an hour?

A) \(15 (\frac{4x}{4})\)
B) \(60(\frac{3x}{y})\)
C) \(15(\frac{16x}{y})\)
D) \(60(\frac{x}{y})\)
E) \(60(\frac{x}{3y})\)

Preferably detailed algebraic solution please.



Hi,

John can eat x doughnuts in y min
so, chen will eat 3x in y mins
Both can eat x+3x in y mins..
If in y min, Both can eat 4x.

in 1 min, both will eat \(4\frac{x}{y}..\)
and in 60 min or 1 hr, both will eat= \(60*\frac{{4x}}{y} = 15 *\frac{{16x}}{y}\)
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Re: John can eat x doughnuts in y minutes. If Chen can eat doughnuts three  [#permalink]

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New post 14 Jan 2019, 19:23
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Re: John can eat x doughnuts in y minutes. If Chen can eat doughnuts three   [#permalink] 14 Jan 2019, 19:23
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