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26 May 2018, 12:01
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
44% (02:34) correct
56%
(02:30)
wrong
based on 101
sessions
History
Date
Time
Result
Not Attempted Yet
John draws two cards at random from a pack of 52 cards. After returning them to the pack and shuffling it, George draws two cards at random. The probability that they have exactly one common card is:
A) \(\frac{25}{546}\)
B) \(\frac{25}{663}\)
C) \(\frac{48}{663}\)
D) \(\frac{50}{663}\)
D) None of these
A) \(\frac{25}{546}\)
B) \(\frac{25}{663}\)
C) \(\frac{48}{663}\)
D) \(\frac{50}{663}\)
D) None of these
26 May 2018, 21:20
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gmatbusters
ways to pick two cards = \(52C2=\frac{52*51}{2}=26*51\)
let one is common so 2 ways and the second one can be any of the remaining 50 so \(2*50\)
probability = \(\frac{2*50}{26*51}=\frac{50}{663}\)
D
22 Jun 2018, 16:02
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chetan2u
Can you please check my answer:
We have 2 possibilities:
P of the first card is the common = (1/52)*(50/51)*2 ==> 2 for the sequence
P of the second card is the same.
Adding both: (1/52)*(50/51)*2*2 = 50/663
Can you please check my answer:
We have 2 possibilities:
P of the first card is the common = (1/52)*(50/51)*2 ==> 2 for the sequence
P of the second card is the same.
Adding both: (1/52)*(50/51)*2*2 = 50/663
