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John would have reduced the time it took him to drive from his home to
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23 Dec 2015, 14:17
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Question Stats:
76% (02:09) correct 24% (01:56) wrong based on 204 sessions
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John would have reduced the time it took him to drive from his home to a certain store by 1/3 if he had increased his average speed by 15 miles per hour. What was John's actual average speed, in miles per hour, when he drove from his home to the store?
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27 Dec 2015, 08:48
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Hi All,
This question is based on a math 'truism' that many Test Takers don't know: Increasing your speed by 50% decreases the amount of travel time by 1/3. Here's why:
Distance = (Rate)(Time)
D = (R)(T)
Since the distance remains the same (you're just changing the rate and time), any increase in rate or time is met with a change in the other term. Increasing the rate by 50% would give us...
D = (3/2)(R)(?)
The change in time has to 'offset' the (3/2) that is now part of the calculation. The fraction (2/3) creates that 'offset', which gives us....
D = (3/2)(R)(2/3)(T)
D = (6/6)(R)(T)
In this prompt, we're told that the time is decreased by 1/3 after the 15 miles/hour increase in speed. We're asked for the ORIGINAL speed, which means that the 15 miles/hour represents the 50% increase. Thus, the original speed must be 30 miles/hour.
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23 Dec 2015, 14:36
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RSOHAL wrote:
John would have reduced the time it took him to drive from his home to a certain store by 1/3 if he had increased his average speed by 15 miles per hour. What was John's actual average speed, in miles per hour, when he drove from his home to the store?
(A) 25 (B) 30 (C) 40 (D) 45 (E) 50
Source: GMAT Focus
Let v,t be the original speed and time taken by John
As the total distance (=speed*time) must be the same,
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23 Jan 2016, 09:26
Engr2012 wrote:
RSOHAL wrote:
John would have reduced the time it took him to drive from his home to a certain store by 1/3 if he had increased his average speed by 15 miles per hour. What was John's actual average speed, in miles per hour, when he drove from his home to the store?
(A) 25 (B) 30 (C) 40 (D) 45 (E) 50
Source: GMAT Focus
Let v,t be the original speed and time taken by John
As the total distance (=speed*time) must be the same,
v*t = (2t/3)*(v+15) ---> v=30 miles per hour.
B is the correct answer.
I like the way you approached the question. I tried to solve the question in a similar way, but without success
the new time given is equal to x-1/3, while the distance is the same and the John's rate changed, which is equal to Disatnce/time - 1/3. In this way I got this equation: x-1/3=D/T-1/3... after that I was stucked.
Re: John would have reduced the time it took him to drive from his home to
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23 Jan 2016, 10:01
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pepo wrote:
Engr2012 wrote:
RSOHAL wrote:
John would have reduced the time it took him to drive from his home to a certain store by 1/3 if he had increased his average speed by 15 miles per hour. What was John's actual average speed, in miles per hour, when he drove from his home to the store?
(A) 25 (B) 30 (C) 40 (D) 45 (E) 50
Source: GMAT Focus
Let v,t be the original speed and time taken by John
As the total distance (=speed*time) must be the same,
v*t = (2t/3)*(v+15) ---> v=30 miles per hour.
B is the correct answer.
I like the way you approached the question. I tried to solve the question in a similar way, but without success
the new time given is equal to x-1/3, while the distance is the same and the John's rate changed, which is equal to Disatnce/time - 1/3. In this way I got this equation: x-1/3=D/T-1/3... after that I was stucked.
Where did I fail?
The mistake you are doing is that when you are told that the time is reduced by 1/3 it's not x-1/3 but x-x/3 = 2x/3
Re: John would have reduced the time it took him to drive from his home to
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23 Jan 2016, 12:32
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Hi pepo,
In this question, the changes in rate and time are based on 'ratios' (NOT on an absolute number).
For example, if you're traveling 60 miles/hour and you reduce THAT speed by 1/3, the calculation is NOT 60 - 1/3.... it's 60 - (1/3)(60) = 40.
Since most of your other math 'skills' seem fine, this issue is ultimately about your organization and how you take your notes. Instead of just writing down "- 1/3", you should think about what that difference represents (it represents a 1/3 decrease in speed) and add a bit more detail to your work.
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02 Mar 2018, 07:49
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Top Contributor
RSOHAL wrote:
John would have reduced the time it took him to drive from his home to a certain store by 1/3 if he had increased his average speed by 15 miles per hour. What was John's actual average speed, in miles per hour, when he drove from his home to the store?
(A) 25 (B) 30 (C) 40 (D) 45 (E) 50
Source: GMAT Focus
Let's start with a word equation: (John's travel time at faster speed) = 2/3(John's regular travel time)
Let r = John's regular speed So, r+15 = John's faster speed Let d = the distance traveled at regular speed So d = the distance traveled at regular speed
time = distance/speed So, we get: d/(r + 15) = (2/3)(d/r) Rewrite as: d/(r + 15)= 2d/3r Cross multiply: (d)(3r) = 2d(r + 15) Expand: 3rd = 2rd + 30d Rearrange to get: rd = 30d Divide both sides by d to get: r = 30
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04 Aug 2019, 05:43
This is my approach. Time (t)= distance(d)/speed(s) This means t is inversely proportional to speed In this case the distance is the constant since it’s the same and can be ignored since it will cancel out in the equations. So we can say that t=1/s ........(a) Where t is the original time taken by John to travel home at a speed of s
We are told that he can reduce his speed by 1/3 had he increased his average speed by 15mph.
So new time would now be 2t/3 and will correspond to a speed of s+15 Hence 2t/3=1/(s+15) So t=3/(2(s+15)) ........(b)
equating (a) to (b)
1/s=3/(2s+30) 3s=2s+30 Hence s=30
Answer is therefore B
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gmatclubot
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04 Aug 2019, 05:43
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76% (02:09) correct 
