Last visit was: 19 Jul 2025, 13:27 It is currently 19 Jul 2025, 13:27
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Jul 2025
Posts: 102,625
Own Kudos:
Given Kudos: 98,235
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 102,625
Kudos: 742,773
 [14]
1
Kudos
Add Kudos
12
Bookmarks
Bookmark this Post
User avatar
Archit3110
User avatar
Major Poster
Joined: 18 Aug 2017
Last visit: 19 July 2025
Posts: 8,353
Own Kudos:
4,833
 [1]
Given Kudos: 243
Status:You learn more from failure than from success.
Location: India
Concentration: Sustainability, Marketing
GMAT Focus 1: 545 Q79 V79 DI73
GPA: 4
WE:Marketing (Energy)
GMAT Focus 1: 545 Q79 V79 DI73
Posts: 8,353
Kudos: 4,833
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
freedom128
Joined: 30 Sep 2017
Last visit: 01 Oct 2020
Posts: 942
Own Kudos:
1,327
 [1]
Given Kudos: 402
GMAT 1: 720 Q49 V40
GPA: 3.8
Products:
GMAT 1: 720 Q49 V40
Posts: 942
Kudos: 1,327
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
eakabuah
User avatar
Retired Moderator
Joined: 18 May 2019
Last visit: 15 Jun 2022
Posts: 782
Own Kudos:
1,112
 [1]
Given Kudos: 101
Posts: 782
Kudos: 1,112
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Cost of a large dresser(L) = $31, Cost of a small dresser(S) = $25. We are to determine S.

To save time in solving this question, it is better to combine both statements.
1+2
Total cost of dressers bought is 280 and the number of small and large dressers are the same.
\(31S+25S=280\)
\(56S=280\)
\(S=5\)

Clearly, we can see that statement 1 is insufficient, hence no need to bother with it.
Step two is to find out if there is any other combination of \(31L+25S=280\), where \(L\) and \(S\) are positive integers.
\(25S=280-31L\)
\(S=\frac{56}{5} - \frac{31}{25}L\)
The only condition for which S can be a positive integer is if S=5.
Therefore, statement 2 alone is sufficient.

The answer is therefore B.
User avatar
exc4libur
Joined: 24 Nov 2016
Last visit: 22 Mar 2022
Posts: 1,702
Own Kudos:
Given Kudos: 607
Location: United States
Posts: 1,702
Kudos: 1,431
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Quote:
Jose purchased several large and small dressers at a flea market to add to his antique furniture collection. The large dressers cost $31 apiece, while the small dressers cost $25 apiece. If Jose did not purchase any other items at the flea market, how many small dressers did he buy?

(1) Jose purchased as many small dressers as large dressers.

(2) In total, Jose spent $280 at the flea market.

(1) insufic

(2) sufic
31a+25b=280
31a's unit digit must be 5 to add to 25b and become 0
31*5=155, 280-155=125=25*5
so, 5 large and 5 small

ans (B)
User avatar
madgmat2019
Joined: 01 Mar 2019
Last visit: 17 Sep 2021
Posts: 588
Own Kudos:
Given Kudos: 207
Location: India
Concentration: Strategy, Social Entrepreneurship
GMAT 1: 580 Q48 V21
GPA: 4
Products:
GMAT 1: 580 Q48 V21
Posts: 588
Kudos: 595
Kudos
Add Kudos
Bookmarks
Bookmark this Post
large costs-31, no.of large-l
small costs-25, no.of small-s

(1) Jose purchased as many small dressers as large dressers.
i.e l=s......but not going to help us in knowing the count of each................INSUFFICIENT

(2) In total, Jose spent $280 at the flea market.
i.e 31l+25s=280..............one equation 2 unknowns...........INSUFFICIENT

combing both we can get the number price of each............SUFFICIENT

OA:C
User avatar
ravigupta2912
User avatar
Current Student
Joined: 26 May 2019
Last visit: 16 Feb 2025
Posts: 726
Own Kudos:
286
 [1]
Given Kudos: 84
Location: India
GMAT 1: 650 Q46 V34
GMAT 2: 720 Q49 V40
GPA: 2.58
WE:Consulting (Consulting)
Products:
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Wrote B, since only 1 combination (5 large and 5 small) is possible if Jose "spent" a total of $280.

The answer would have been D if Jose "had" $280 with him aka the spending was discretionary since in that case, Jose could have either got 8 large or 11 small dressers or some combination of large and small.
User avatar
PoojanB
Joined: 09 May 2017
Last visit: 08 Dec 2020
Posts: 81
Own Kudos:
94
 [1]
Given Kudos: 69
Location: India
GMAT 1: 610 Q42 V33
GMAT 2: 620 Q45 V31
GPA: 4
WE:Engineering (Energy)
GMAT 2: 620 Q45 V31
Posts: 81
Kudos: 94
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let Large dresser qty=L
Small dresser qty=S
Given= Cost of large dresser= 31$/piece
Cost of small dresser=25$/piece


STA-- L=S. L & S can take any positive integer value.

STB---31L+25Y=280 now , only L=5,Y=5 solves the equation (as L & Y can take positive integer values)
Hence ,STB by itself is sufficient

Ans B
User avatar
unraveled
Joined: 07 Mar 2019
Last visit: 10 Apr 2025
Posts: 2,727
Own Kudos:
2,172
 [1]
Given Kudos: 763
Location: India
WE:Sales (Energy)
Posts: 2,727
Kudos: 2,172
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Jose purchased several large and small dressers at a flea market to add to his antique furniture collection. The large dressers cost $31 apiece, while the small dressers cost $25 apiece. If Jose did not purchase any other items at the flea market, how many small dressers did he buy?

31*l + 25*s = 280. s = ?

(1) Jose purchased as many small dressers as large dressers.
l = s
Any number of values are possible.

INSUFFICIENT.

(2) In total, Jose spent $280 at the flea market.
31*l + 25*s = 280
Only possibility is l = 5 and s = 5 as both l and s are positive integers.

SUFFICIENT.

Answer B.
User avatar
monikakumar
Joined: 23 Jan 2020
Last visit: 31 Dec 2021
Posts: 236
Own Kudos:
Given Kudos: 467
Products:
Posts: 236
Kudos: 145
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Jose purchased several large and small dressers at a flea market to add to his antique furniture collection. The large dressers cost $31 apiece, while the small dressers cost $25 apiece. If Jose did not purchase any other items at the flea market, how many small dressers did he buy?

(1) Jose purchased as many small dressers as large dressers.

(2) In total, Jose spent $280 at the flea market.

stem: x -> no of small dress, y-> no of large dress

1) x=y, not sufficient for x
2) x25+y31=280, x=y=5, sufficient
so Ans B
User avatar
globaldesi
Joined: 28 Jul 2016
Last visit: 03 Jun 2025
Posts: 1,159
Own Kudos:
Given Kudos: 67
Location: India
Concentration: Finance, Human Resources
Schools: ISB '18 (D)
GPA: 3.97
WE:Project Management (Finance: Investment Banking)
Products:
Schools: ISB '18 (D)
Posts: 1,159
Kudos: 1,904
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Jose purchased several large and small dressers at a flea market to add to his antique furniture collection. The large dressers cost $31 apiece, while the small dressers cost $25 apiece. If Jose did not purchase any other items at the flea market, how many small dressers did he buy?

let small be x and large be y


(1) Jose purchased as many small dressers as large dressers.
given x = y
but we cant say what is the maximum value.
Not sufficient

(2) In total, Jose spent $280 at the flea market.

given 31y+25x = 280

x and y has to be positive integers

or 25x= 280-31y
only value satisfy that x and y are both integers is
x= 5 and y =5
thus sufficient B

Thus B is the answer
User avatar
Sourav_Dey
Joined: 05 Apr 2024
Last visit: 19 Apr 2025
Posts: 6
Own Kudos:
Given Kudos: 72
Products:
Posts: 6
Kudos: 3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
D shall be the answer.

Opt 1: if no of both furniture is x then 31x+25x=280-> x= 5 Sufficient

Opt 2: as numbers of large or small dresser is integer value…31x+25y=280….only possible solution is x=y=5 sufficient

Posted from my mobile device
User avatar
RishabhAwasthi
Joined: 07 Oct 2020
Last visit: 02 Jun 2025
Posts: 2
Given Kudos: 330
Posts: 2
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
This is a classic C trap question.

Taking the number of Larger dressers as L and number of small dressers as S.

Statement 1 : This simply means L = S and it doesn't help in finding the S. NOT SUFFICIENT


Statement 2: 31L + 25S = 280

On closely observing, there will be only one solution to this equation.
We know that anything multiplied to 25 will end up with either 5 or 0 as a unit digit and since we need 0 as the unit digit of the final answer, this can only happen when we have 5 as a unit digit from 31L.

Start by finding the closest multiple of 5 with 31. This happens to be 155 , which means L = 5.

Now putting this back in our equation.

31*5 + 25S = 280
155 + 25S = 280
25S = 125
S = 5

This is our answer. Hence Statement 2 is SUFFICIENT
User avatar
Ab295
Joined: 24 Nov 2024
Last visit: 15 Feb 2025
Posts: 44
Own Kudos:
Given Kudos: 24
GMAT Focus 1: 645 Q87 V81 DI77
GMAT Focus 1: 645 Q87 V81 DI77
Posts: 44
Kudos: 24
Kudos
Add Kudos
Bookmarks
Bookmark this Post
All explanations are hidden Bunuel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Jul 2025
Posts: 102,625
Own Kudos:
Given Kudos: 98,235
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 102,625
Kudos: 742,773
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Ab295
All explanations are hidden Bunuel

Fixed that. Thank you!
Moderators:
Math Expert
102625 posts
455 posts