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Joseph's final grade is calculated from the mean of his test scores.

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Joseph's final grade is calculated from the mean of his test scores.  [#permalink]

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New post 31 Jan 2019, 00:41
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Joseph's final grade is calculated from the mean of his test scores. His teacher also allows them to drop the lowest score before calculating the final grade. If Joseph received a (67, 82, 73, 91, 77, and, 75) on his tests, what was his final grade rounded to the nearest whole number?


A. 78

B. 79

C. 80

D. 81

E. 82

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Re: Joseph's final grade is calculated from the mean of his test scores.  [#permalink]

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New post 31 Jan 2019, 02:19
Bunuel wrote:
Joseph's final grade is calculated from the mean of his test scores. His teacher also allows them to drop the lowest score before calculating the final grade. If Joseph received a (67, 82, 73, 91, 77, and, 75) on his tests, what was his final grade rounded to the nearest whole number?


A. 78

B. 79

C. 80

D. 81

E. 82


lowest score in set = 67
sum of rest = 398
avg 398/5 = 79.6 ~80
IMO C
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Re: Joseph's final grade is calculated from the mean of his test scores.  [#permalink]

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New post 31 Jan 2019, 07:06

Solution


Given:
    • Final grade is calculated from the mean of the test scores
    • They are allowed to drop the lowest score before calculating the final grade
    • Joseph received scores of {67, 82, 73, 91, 77, 75} on his tests

To find:
    • The final grade rounded to the nearest integer

Approach and Working:
    • The least score among the given set of scores = 67
    • The sum of the remaining scores = 82 + 73 + 91 + 77 + 75 = 398
    • Thus, mean = \(\frac{398}{5} = 79.6 ≃ 80\)

Hence, the correct answer is Option C

Answer: C

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Re: Joseph's final grade is calculated from the mean of his test scores.  [#permalink]

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New post 04 Feb 2019, 19:19
Bunuel wrote:
Joseph's final grade is calculated from the mean of his test scores. His teacher also allows them to drop the lowest score before calculating the final grade. If Joseph received a (67, 82, 73, 91, 77, and, 75) on his tests, what was his final grade rounded to the nearest whole number?


A. 78

B. 79

C. 80

D. 81

E. 82


Since 67 is the lowest score and will be dropped, the final grade is:

(82 + 73 + 91 + 77 + 75)/5 = 398/5 = 79.6 ≈ 80

Answer: C
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Joseph's final grade is calculated from the mean of his test scores.  [#permalink]

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New post 04 Feb 2019, 19:33
Bunuel wrote:
Joseph's final grade is calculated from the mean of his test scores. His teacher also allows them to drop the lowest score before calculating the final grade. If Joseph received a (67, 82, 73, 91, 77, and, 75) on his tests, what was his final grade rounded to the nearest whole number?


A. 78

B. 79

C. 80

D. 81

E. 82


So because of this, we can remove 67

(73 + 75 + 77 + 82 + 91) / 5

398/ 5

79.6

80

C
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Re: Joseph's final grade is calculated from the mean of his test scores.  [#permalink]

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New post 11 Feb 2019, 05:30
Drop 67 since it is lowest

=> sum of all the numbers excluding 67= 398
=>Avg =398/5 = 79.6 ~80

Option C is correct.
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Re: Joseph's final grade is calculated from the mean of his test scores.   [#permalink] 11 Feb 2019, 05:30
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