Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jul 1206:30 AM PDT
-08:30 AM PDT
Join our webinar to master GMAT RC Main Point Questions! Learn effective strategies to decipher passage themes and purposes. Senior Verbal Expert- Sunita Singhvi will equip you with tools to navigate complexities and avoid common traps set by the GMAT.
Jul 1211:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.
Jun 3008:00 AM PDT
-11:59 PM PDT
Join us June 30th for 2 weeks of GMAT questions (just 8 per day) to help with your prep and to compete with your fellow GMAT Clubbers for a chance to win a prize fund of $30,000 for you and your team-mates!
Jul 0901:00 PM EDT
-02:00 PM EDT
More Target Test Prep students are earning 100th percentile GMAT scores. Don’t settle for less when the Target Test Prep course gives you everything you need to score high on the GMAT. Start your 5-day free trial today.
Jul 1311:00 AM EDT
-12:30 PM EDT
Looking for your GMAT motivation to break through the score plateau? Pragati improved her score by massive 160 points with strategic guidance and hard-work! Find out how personalized mentorship and a strong mindset can turn GMAT struggles into success.
Jul 1508:00 PM PDT
-09:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Jul 1611:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
18 May 2020, 09:10
Kudos
Bookmarks
Chethan92
From statement 1:
\(5<2x<12\)
\(2.5<x<6\) x can be 3, 4 or 5.
If 3 pies then 8*3 = 24 slices. Not enough
If 4 or 5 pies then 32 or 40 slices. Enough.
Insufficient.
From statement 2:
x is a multiple of 3.
Already given that x > 0. So, min value of x can be 3. Then [x] is 3. Then 8*3 = 24 pies. Not enough.
If x is 6 then 48 pies. Enough.
InSufficient.
Combining both gives only x as 3. So 24 pies. Not enough.
C is the answer.
\(5<2x<12\)
\(2.5<x<6\) x can be 3, 4 or 5.
If 3 pies then 8*3 = 24 slices. Not enough
If 4 or 5 pies then 32 or 40 slices. Enough.
Insufficient.
From statement 2:
x is a multiple of 3.
Already given that x > 0. So, min value of x can be 3. Then [x] is 3. Then 8*3 = 24 pies. Not enough.
If x is 6 then 48 pies. Enough.
InSufficient.
Combining both gives only x as 3. So 24 pies. Not enough.
C is the answer.
I have some doubts toward the definition of “sufficient & insufficient”, at first I thought “sufficient” indicate that we could, by using the information given, infer whether each guest can have at least one slice”, or say, whether statement (1)/(2) is sufficient or not to make the question be inferable
It seems everyone agree on this ---“not enough for each 30 guest to have one pie” equal “insufficient”, I’m not sure whether there are some blind spots in my thinking to the definition of sufficient/ insufficient, if (1) is inferable then shouldn’t that this statement be sufficient to infer whether 30 guests could all get their pie?hopes someone could shed light on this, thanks
03 Aug 2020, 11:37
Kudos
Bookmarks
30 slices required
8 slices per pizza
So we need at least 4 pizzas
(1) 5<2x<12
2.5<x<6
when x=2.6, ⌈x⌉=3, NOT ENOUGH PIZZA
when x=3, ⌈x⌉=4, YES ENOUGH PIZZA
Insufficient
(2) x=3,6,9,....
when x=3, ⌈x⌉=4, YES ENOUGH PIZZA
when x=6, ⌈x⌉=7, YES ENOUGH PIZZA
Sufficient
Answer: B
8 slices per pizza
So we need at least 4 pizzas
(1) 5<2x<12
2.5<x<6
when x=2.6, ⌈x⌉=3, NOT ENOUGH PIZZA
when x=3, ⌈x⌉=4, YES ENOUGH PIZZA
Insufficient
(2) x=3,6,9,....
when x=3, ⌈x⌉=4, YES ENOUGH PIZZA
when x=6, ⌈x⌉=7, YES ENOUGH PIZZA
Sufficient
Answer: B
03 Aug 2020, 12:20
Kudos
Bookmarks
AbhishekDhanraJ72
XavierAlexander
Julie wants to be sure that she has enough pies for each of her 30 guests to have at least one slice. One pie can be divided into eight slices. If \(⌈x⌉\)represents the least integer greater than \(x\), and \(x\) is greater than \(0\), will \(⌈x⌉\) pies be enough for each guest to have at least one slice?
(1) \(5 < 2x < 12\)
(2) \(x\) is a multiple of \(3\)
(1) \(5 < 2x < 12\)
(2) \(x\) is a multiple of \(3\)
if [x] represents the least integer greater than x is [3] then means x=4 ???
Here, ⌈x⌉ represents the number of pies (x is not the number of pies).
From 1: 5 < 2x < 12 => 2.5 < x < 6
=> 3 < ⌈x⌉ < 6
Note: ⌈x⌉ is the least integer GREATER THAN x (not the usual - greater than or equal to x)
The value of ⌈x⌉ could be:
x = 2.6 => ⌈x⌉ = 3 - not enough pies
x = 3 => ⌈x⌉ = 4 - enough pies
x = 3.4 => ⌈x⌉ = 4
x = 4 => ⌈x⌉ = 5
x = 4.2 => ⌈x⌉ = 5
x = 5 => ⌈x⌉ = 6
x = 5.6 => ⌈x⌉ = 6
Since each pie can be divided in 8 pieces, we need at least 4 pies (4 x 8 = 32 pieces) for 30 people (3 pies would give only 24 pieces - falls short)
Thus, the above statement is NOT SUFFICIENT
From 2: x is a positive integer and a multiple of 3
=> Minimum value of x = 3
=> ⌈x⌉ = 4 - enough pies
Thus, the above statement is SUFFICIENT
Answer B
