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Bunuel
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The store keeps selling 20% or 1/5 of its stock daily, without replacing. So at the end of the day, the stock that remains is 4/5 of the original stock. We have to find the fraction after four days, which means we have to multiply the original value four times by 4/5.

So lets start with a number '625' which represents the original stock. (because 625 = 5^4)
Thus, stock after 4 days = 625 * 4/5 * 4/5 * 4/5 * 4/5 = 256.
Stock remaining = 625-256 = 369

So the required fraction = 369/625

Hence E is answer
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Bunuel
During a sale, a store sells 20 percent of its remaining stock each day, without replenishment. After four days, what fraction of its original stock has it sold?

A. 1/625
B. 256/625
C. 61/125
D. 64/125
E. 369/625

We can let the initial stock = x.

After day 1:

0.2x is sold and 0.8x is left over.

After day 2:

0.2(0.8x) = 0.16x is sold and 0.8(0.8x) = 0.64x is left over.

After day 3:

(0.2)(0.64x) = 0.128x is sold and 0.8(0.64x) = 0.512x is left over.

After day 4:

0.2(0.512x) = 0.1024x is sold and 0.8(0.512x) = 0.4096x is left over.

Since 0.4096x is left over at the end of 4 days, 1 - 0.4096 = 0.5904, or 59.04%, of the initial stock was sold. We re-express 0.5904 as a fraction: 0.5904 = 5904/10,000 = 738/1250 = 369/625 of the original stock was sold.

Answer: E
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Most easiest option i guess is use fraction i.e. first day 1/5 of X is sold and next day 4/5 of the stock remained.
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Bunuel
During a sale, a store sells 20 percent of its remaining stock each day, without replenishment. After four days, what fraction of its original stock has it sold?

A. 1/625
B. 256/625
C. 61/125
D. 64/125
E. 369/625

\(20\) % = \(\frac{1}{5}\)

Thus, there is a reduction in stock by the fraction of \(\frac{1}{5}^{th}\)

Let, The total stock be 625 Units....

Day 1 : Stock in Hand = 625, Sold = 125, Remaining = 500
Day 2 : Stock in Hand = 500, Sold = 100, Remaining = 400
Day 3 : Stock in Hand = 400, Sold = 80, Remaining = 320
Day 4 : Stock in Hand = 320, Sold = 64, Remaining = 256

Total Quantity of Stock sold is 625 - 256 = 369 Units...

Quote:
After four days, what fraction of its original stock has it sold?

So, fraction of Original Stock he has is \(\frac{369}{625}\)

Thus, Answer must be (C) \(\frac{369}{625}\)
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I guess the easiest approach is to subtract the remaining stock from the original:

\(1-(\frac{4}{5})^4\)
\(=\frac{625}{625}-\frac{256}{625}\)
\(=\frac{369}{625}\)
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I chose my smart number as 625. Why? because it's in answer choices.

In the end just build a quick calculation matrix of day/inventory/sold and work your way through 4 days. It took me less than 2 minutes to calculate.
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Taking a clue from the choices, we could take the initial amount as 625. The answer is choice E.

Harsha
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20% of beginning amount will be sold on first day..... So 80% of beginning amount will be left for da second day.....so 80% of something is the same as multiplying the thing with 4/5 .......
So da amount that gets left out at the end of a day = beginning amount × ( 4/5 )^number of days passed = beginning amount × ( 4/5 )^4 = beginning amount × 4/5 × 4/5 × 4/5 × 4/5
So....da lets pick a number as beginning amount that is divisible by 5^4 ............ Ta-da...its 625........so amount left after 4 days is = 625 × (4^4)/(5^4) = 625 × 256/625 = 256 ...so amount sold in 4 days = 625 - 256 = 369... So fraction sold 369/625...
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