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# Kevin flips a coin four times. WHat is the probability the he gets hea

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Re: Kevin flips a coin four times. WHat is the probability the he gets hea [#permalink]

P (0 Head)= (1/2)*(1/2)*(1/2)*(1/2) = (1/16)

Probability of getting Head on at least one flip of four =1- P (0 Head) = 1- (1/16) = (15/16)

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Kevin flips a coin four times. WHat is the probability the he gets hea [#permalink]
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P(0H) + P(1H) + P(2H) + P(3H) + P(4H) = 1
=> P(1H) + P(2H) + P(3H) + P(4H) = 1 - P(0H)

P(At least 1 H) = 1 - P(0H)

1 - P(4T) = 1 - $$\frac{1}{2}*\frac{1}{2}*\frac{1}{2}*\frac{1}{2}$$ = 1 - $$\frac{1}{16}$$ = $$\frac{15}{16}$$

Hope it helps!

Watch the following video to learn How to Solve Probability with Coin Toss Problems

Kevin flips a coin four times. WHat is the probability the he gets hea [#permalink]
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