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Answer choice is C

Explanation

The prompt tells us that 4^w=n and asks us to find the units digits of n. In order to find the units digit of n we need to find the value of w. so basically we can rephrase this question as - what is the value of w?


Statement 1 tells us that w is an even integer but does not provide the exact value of w. so is it insufficient? not so fast let's see if there is a pattern in the value of 4 to the power of a even number by which we can determine the units digit of n. if you plug in few even numbers you realize there is a pattern and units digit is always 6.

For example
4^2= 16
4^4=256
4^6=4096
4^8=65,536


so is it sufficient? not so fast. did you forget something? well yes. This is classics GMAT trap- 0 is even number and people often forget that. 4 ^0 is 1. Even though we had good pattern when w =2 or 4, or 6 the units digit was 6 but when w = 0 the units digit is 1. Thus, the information provided by statement 1 alone is Not sufficient to determine the units digit of n. Eliminate answer choices A and D.

Statement 2
tells us that w is > 0. Now let's forget what was provided in statement 1 and focus just on statement 2 information. when w>0 it can be any value starting from 1 resulting in different values of n. Thus information provided by statement 2 alone is not sufficient to determine the unit digits of n. Eliminate answer choice B. The correct answer must be either C or E.

Taking the statements together, we know from statement 1 that the value of w is even and from statement 2 that
w > 0 therefore w is even number > 0. so it must be 2 or 4 or 6 or 8 etc. we know from above plugging exercise that there is a pattern and units digit of n is always 6. Thus both statements together are sufficient to answer the question.

Answer choice C is correct.
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The answer is A, Statement 1 is sufficient.

4^2 is 16. 4^4 is 256. 4 to any odd power results in a 6 for the units digit of n. 4 to any even power results in a 4 for the units digit of n.

Therefore, Statement 1 says that w is even, and therefore the units digit of n is always 6, whether positive or negative. Sufficient.

Statement 2 says w is greater than zero, so it is either even or odd, therefore the units digit is 6 or 4. Insufficient.

Correct Answer: A
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The Answer for the above question is
choice
(C) BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Explanation :
4^w = n
As per Statement 1
If W is an even integer,it can be either positive even or negative even integer.
Case 1:
--------
If W is positve even integer,then the unit's digit of n will be 6 .
For ex. 4^2 = 16, 4^4 = 256
Case 2:
-------
But if w is negative even integer, it will not be 6.
For ex. 4^-2 = 0.0625
Since there is no unique answer, Statement 1 alone is not enough to answer the question.

As per Statement 2
w > 0
So w can be either positive even integer or positive odd integer.
Case 1:
--------
If w is positive even integer,
then the unit digit of n will be 6.
For ex. 4^2 = 16, 6^4 = 256

Case 2:
--------
If w is negative integer,
then the unit integer of n will be 4.
For ex. 4^1 = 4, 4^3 = 64

Since there is no unique answer, Statement 2 alone is not sufficient.

but combining both the statements 1 and 2,
we can conclude that the w is positive even integer.
So the unit digit of n will always be 6.
So the Answer choice is C.
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The answer is C.

The unit digit of 4^w is either 4 or 6.
If "w" is positive odd number, the unit digit will be 4.
If "w" is positive even number, the unit digit will be 6.

Now look at the statements:
a) w is even integer.
4^2 = 16; 4^4 = 256; 4^6 = 4096 and so on
but 4^-2 will not end with 6...
so, a alone is not sufficient/

b) w>0
4^1 =4 while 4^2 = 16
So unit digit can be 4 or 6.
Hence not sufficient.

However if w>0 and is even number, the unit digit will be 6 always.
Hence, both statements are required for answer.
So option C is correct.
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If 4^w = n, what is the units digit of n?

1. w is an even integer
2. w > 0

Solution: (C)

Rephrasing : 4^w=n : 2^(2w). 2,4,8,6 -- repeat cycle of unit digit of 2^x. Where x is an integer. So basically we have to figure out What is W?

1) Let w=2,4, 6. 2^2w will have unit digit of 6 in all the cases. Check w=0. {0 is also an even integer). Unit digit will be 1. NS.

2) w>0 . w=1; unit digit is 4.
w=2; unit digit is 6
NS.

Combining Together. Since w>0. All other values satisfying 1 will have unit digit of 6
Sufficient.

C is the correct Option. :)

Takeaway : { 0 is an even Integer} :wink:
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The cyclicity for 4 is 2. i.e The units digit of any power of 4 is either 4 or 6( 4^1=4, 4^2=16, 4^4=64...) Therefore an even power of 4 will have the units digit of 6 wheras an odd power of 4 will have units digit 4.

Statement 1: W is an even integer. How ever w can be a -ve even integer. 4^-2 = (1/4)^2 = 0.0625.
Therefore statement 1 alone is not sufficient

Satement2: W>0 . This is not sufficient as W can be even or odd and the units digit of 4^w will vary depending on whether w is even or odd.

Now, combining both w>0 and w is even we can tell that all positive even powers of 4 have units digit 6. Answer is C
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statement 1 --> w is even --> w can be 0, 2, 4.. 10.. 100 --> 4^0 = 1, 4^2 = 16 --> insufficient

Statement 2 --> w > 0 --> w can be 1, 2.. etc. --> 4^1 = 4, 4^2 = 16 again unit digits are different --> insufficient

taken together it is sufficient as the units digits will always be 6 for all even numbers > 0.

ans c
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If 4^w = n, what is the units digit of n?

1. w is an even integer
2. w > 0

Sol:
4^w = unit Digit 4 : when w is odd and >0
4^w = Unit Digit 6 : when w is even and >0

Statement 1: w is an even integer
4^2 = 16 4^4 = 256
4^-2 =1/16=0.0625
not sufficient

Statement 1: w > 0
4^1 = 4 4^2 =16
4^3 = 64 4^4=256

Not sufficient

Combining together:
w >0 and even.
then unit digit will always be 6.

Correct Ans C.
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THE ANSWER IS C

4^w = n
the unit digit will be 6.

for 4^w, if w<0, it will become a fraction. so w>0 is necessary

let w=2k,
then 4^w = 4^2k = 16^k.

write 16^k = (10+6)^k and now expand usig binomial theorem.

Each term will contain a factor of 10^something except the last term i.e kCk 6^k.
So units place will contain 6.
Hence both statements are necessary and sufficient.

If we take w=2k+1, the last term will come 4.
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Answer to the question is A: 1 alone is sufficient.

1. Rule : All even powers of 4 will have 6 as the units digit. all odd powers of 4 will have 4 as units digit.

2. W > 0 : can be even or odd or even a fraction : hence insufficient.

Regards,
Raghav.V
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Ans C
We will raise 4 to powers from 0 onwards to check for a pattern in the units digit of the answers.
4^0 = 1
4^1 = 4
4^2 = 16
4^3 = 64
4^4 = 256
4^5 = ...4
4^6 = . ..6
Except for the the first number where 4 is raised to 0,
we see a consistent pattern of 4, 6, 4, 6 repeating in the unit digit of the answers.

Now check stmt 1
w is an even number ie w could be 0, 2, 4, 6..etc. We would get different unit digits.
If w= 0 then n = 1
If w = any other even number, then n = 6
So, since we get 2 answers for n, this statement is Not Sufficient.

Stmt 2
w > 0 ie w could be 1, 2, 3, 4 etc.
If w = odd nos ie 1, 3...., n = 4
If w = even nos ie 2, 4...., n = 6
Again, we get 2 answers for n. Hence statment 2 is Not Sufficient.

Taking statements 1 and 2 together we get:
W is even and greater than 0
W = 2, 4, 6... , therefore n = 6
Since we get only one answer for n ie n = 6
Both 1 and 2 together are Sufficient and the answer is (C)
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1. w is an even integer
Statement 1 alone is not sufficient,
Reason,
if w>0, the unit digit will be "6"
whereas, if w<0, the unit digit will vary depending on the value of w

2. w > 0
Statement 2 alone is not sufficient,
Reason,
if w=1,3,5,7,.... unit digit will be "4"
whereas if w=2,4,6,8,.... unit digit will be "6"


Statement 1 and 2 together will be sufficient and in this case unit digit will be "6"

Therefore C is the correct answer
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C) Both statements together, but neither alone is sufficient
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Answer:(C) BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

1. w is an even integer, 4^0=1, 4^2=16; in these examples the unit digits are 1 and 6 respectively so this alone is not sufficient to answer the question
2. w > 0, 4^1=4, 4^2=16; in these examples the unit digits are 4 and 6 respectively so this alone is not sufficient to answer the question
3. The unit digit of 4 to the power w is 6 when w is even
The unit digit of 4 to the power w is 4 when w is odd
So if w is >0 AND an even integer, the unit digit of the resulting number is always 6
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Ans:A

1. W is given to be an even integer. When 4 is raised to an even power (w = 2, 4, 6, 8 etc), n is 16, 256, 4096, etc. The units digits is always 6. Hence sufficient.

2. w>0. The units digit of n in this case will alternate between 4 and 6 (if w is an integer). Hence insufficient.

Answer Choice A alone is sufficient.
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I shall answer using examples:
1. If w is an even integer then w = {... -2,0,2,4,...}
Now 4^-2 = 0.0625, 4^0 = 1, 4^2 = 16, 4^4 = 256.
Hence we can't be sure of the units digit.
2. If w>0 then w = {1,2,3,...}
Now 4^1 = 4, 4^2 = 16, 4^3 = 64.
Hence we can't be sure of the units digit in this case too.

But if we combine both 1 and 2 then w = {2,4,...}
We know that 4^2 = 16, 4^4 = 256 and so on.
Hence by combining both we can conclude that the units digit will always be 6.

The correct answer is (C).
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If , 4^w = n what is the units digit of n?

1. w is an even integer
2. w > 0

by plugging no.s we can check that for all odd w the units digit of n = 4 and for even w, units digit of n = 6 but w = 0 or w < 0 we have exceptions.

statement 2 clearly obviates all exceptions bt stating w > 0

so combining both the statements we get the answer, while none alone is sufficient alone.

Therefore C is answer
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