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17 Jan 2020, 02:37
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D
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Difficulty:
35%
(medium)
Question Stats:
68% (01:41) correct
33%
(01:52)
wrong
based on 120
sessions
History
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Time
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Not Attempted Yet
Last month, a certain manufacturer sold a total of 1,000 units of its two products, A and B. The selling price of each unit of product A was $1,500, and the selling price of each unit of product B was $2,000. How many units of product A did the manufacturer sell last month?
(1) Last month, the manufacturer's total revenue from the sale of units of products A and B was $ 1,600,000.
(2) Last month, the manufacturer's total revenue from the sale products A was 3 times the manufacturer's revenue from the sale of units of product B.
Are You Up For the Challenge: 700 Level Questions
(1) Last month, the manufacturer's total revenue from the sale of units of products A and B was $ 1,600,000.
(2) Last month, the manufacturer's total revenue from the sale products A was 3 times the manufacturer's revenue from the sale of units of product B.
Are You Up For the Challenge: 700 Level Questions
17 Jan 2020, 09:32
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Bunuel
A+B=1000
A+(1000-A)=1000
Total Revenue=A*1500+(1000-A)*2000
From 1
A*1500+(1000-A)*2000=1,600,000
A=800
Sufficient
From 2
1500*A=3*(1000-A)*2000
A=800
Sufficient
D:)
18 Jan 2020, 01:58
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given
Pa+Pb = 1000
Sa= 1500
Sb = 2000
find Pa
#1Last month, the manufacturer's total revenue from the sale of units of products A and B was $ 1,600,000.
1500*Pa+2000*Pb = 16*10^5
solve for Pa sufficient
#2
Last month, the manufacturer's total revenue from the sale products A was 3 times the manufacturer's revenue from the sale of units of product B.
1500*Pa= 3*2000*Pb
solve for Pa
sufficient
IMO D
Pa+Pb = 1000
Sa= 1500
Sb = 2000
find Pa
#1Last month, the manufacturer's total revenue from the sale of units of products A and B was $ 1,600,000.
1500*Pa+2000*Pb = 16*10^5
solve for Pa sufficient
#2
Last month, the manufacturer's total revenue from the sale products A was 3 times the manufacturer's revenue from the sale of units of product B.
1500*Pa= 3*2000*Pb
solve for Pa
sufficient
IMO D
Bunuel
