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# Last Thursday, John assembled chairs at a rate of 3 chairs

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Joined: 22 Nov 2007
Posts: 1008
Last Thursday, John assembled chairs at a rate of 3 chairs  [#permalink]

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Updated on: 05 Jan 2015, 03:42
1
18
00:00

Difficulty:

45% (medium)

Question Stats:

74% (02:17) correct 26% (02:25) wrong based on 430 sessions

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Last Thursday, John assembled chairs at a rate of 3 chairs per hour for part of the day and Larry assembled no chairs. Last Friday, Larry assembled chairs at a rate of 4 chairs per hour for part of the day and John assembled no chairs. If John and Larry assembled chairs for a total of 7 hours during these two days, how many chairs did John assemble last Thursday?

(1) During these two days, John and Larry assembled a total of 25 chairs.
(2) During these two days, Larry assembled more chairs than John did.

Originally posted by marcodonzelli on 11 Mar 2008, 10:14.
Last edited by Bunuel on 05 Jan 2015, 03:42, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to DS forum.
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Joined: 10 Sep 2007
Posts: 833
Re: Last Thursday, John assembled chairs at a rate of 3 chairs  [#permalink]

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11 Mar 2008, 11:40
3
Suppose John worked J hours and Larry for L hours.
So from question we know that J + L = 7

Statement 1:
Tells that total chairs they collected is 25,
So we can write that 3J + 4L = 25
Now we have two equation and two unknowns so can be easily solved.

Statement 2:
Says Larry assembled more chairs than John. But does not tells how many chair in total they assembelled. So this alone is insufficient.

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Re: Last Thursday, John assembled chairs at a rate of 3 chairs  [#permalink]

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03 Jan 2015, 11:50
Hi All,

Since the numbers involved in this DS question are relatively small, we can "brute force" all of the possible options rather easily (if needed) to prove the correct answer.

We're given the rates of two people:
John assembles 3 chairs/hour
Larry assembles 4 chairs/hour
We're told that 7 hours of total work time was done, but that the two men did not work at the same time.

We're asked how many chairs JOHN assembled.

Assuming that we're not dealing with "fractional chairs", the number of possibilities is really limited - each man worked from 1 to 6 hours, so the possible outcomes are:

John/Larry/Total
3/24/27
6/20/26
9/16/25
12/12/24
15/8/23
18/4/22

Fact 1: A Total of 25 chairs were made.

There's just one option that fits this: John makes 9 and Larry makes 16 --> the answer to the question is 9
Fact 1 is SUFFICIENT

Fact 2: Larry assembled more chairs than John.

Here, we have 3 possibilities: John could have made 3, 6 or 9 chairs.
Fact 2 is INSUFFICIENT

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Re: Last Thursday, John assembled chairs at a rate of 3 chairs  [#permalink]

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06 Jan 2015, 09:53
GIVEN
John's Rate = 3 chairs/hour
Larry's Rate = 4 chairs/hour

In total both of them worked for 7 hours

STATEMENT 1
Let the amount of time John take be J and Larry take be L
Now, we're given that both of them on 2 days created a total of 25 chairs
so using the formula $$r*t=w$$
we get the following equation
$$3J + 4L = 25$$
$$J = \frac{(25 - 4l)}{3}$$
Only 2 pair of values satisfy this equation
$$L=1 and J=7$$
and
$$L=4 and J=3$$
we'll not consider the first equation since the total time they were given was 7 hours, but adding the those two values give us a total of 8
so the only other pair gives us the time, from which we can take out the no of chairs for both of them

Statement 2
Doesn't give us anything to solve for

Ans is A
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Re: Last Thursday, John assembled chairs at a rate of 3 chairs  [#permalink]

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08 Oct 2018, 12:37
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Re: Last Thursday, John assembled chairs at a rate of 3 chairs   [#permalink] 08 Oct 2018, 12:37
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# Last Thursday, John assembled chairs at a rate of 3 chairs

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