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01 May 2017, 10:28
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
64% (03:13) correct
36%
(02:47)
wrong
based on 66
sessions
History
Date
Time
Result
Not Attempted Yet
Last year the average health care cost per employee in Group G increased by \(n\) percent and the average compensation per employee in group G increased by \(m\) percent, where \(n\) is greater than \(m\). By what percent did the ratio of health care cost per employee to compensation per employee increase, in terms of \(n\) and \(m\)?
A. \(\frac{n}{m}\%\)
B. \((n-m)\%\)
C. \(\frac{100(n-m)}{100+n}\%\)
D. \(\frac{100(n-m)}{100+m}\%\)
E. \(\frac{100(n-m)}{100+n+m}\%\)
Source: GMAT Free
A. \(\frac{n}{m}\%\)
B. \((n-m)\%\)
C. \(\frac{100(n-m)}{100+n}\%\)
D. \(\frac{100(n-m)}{100+m}\%\)
E. \(\frac{100(n-m)}{100+n+m}\%\)
Source: GMAT Free
02 May 2017, 08:50
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nguyendinhtuong
The ratio earlier was \(\frac{H}{C}\)...
The increased ratio is \(\frac{H (100+n)}{C(100+m)}\)....
Therefore increase in % is ( \(\frac{H(100+n)}{C (100+m)}-\frac{H}{C}\))*100/(H/C)...
(\(\frac{(100+n)}{(100+m)}-1\))*100....
\(\frac{100+n-100-m}{100+m}*100=\frac{100(n-m)}{100+m}\)%
D
03 May 2017, 12:30
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Hi All,
This is an EXACT "lift" of an OG question:
OG13/GMAT2015 pg., Q177
GMAT2016 pg. 179, Q191
GMAT2017 pg. 180, Q202
Anyone with a connection to Wiley should absolutely forward this post to Wiley. This is blatant theft of intellectual property.
GMAT assassins aren't born, they're made,
Rich
This is an EXACT "lift" of an OG question:
OG13/GMAT2015 pg., Q177
GMAT2016 pg. 179, Q191
GMAT2017 pg. 180, Q202
Anyone with a connection to Wiley should absolutely forward this post to Wiley. This is blatant theft of intellectual property.
GMAT assassins aren't born, they're made,
Rich
