|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
17 May 2018, 05:16
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
93% (00:29) correct
7%
(00:42)
wrong
based on 78
sessions
History
Date
Time
Result
Not Attempted Yet
Laura’s bag contains 14 red marbles and 16 green marbles. If Laura selects one marble at random from the bag, what is the probability that the marble she selects will be green?
A. \(\frac{1}{30}\)
B. \(\frac{7}{15}\)
C. \(\frac{8}{15}\)
D. \(\frac{7}{8}\)
E. \(\frac{8}{7}\)
A. \(\frac{1}{30}\)
B. \(\frac{7}{15}\)
C. \(\frac{8}{15}\)
D. \(\frac{7}{8}\)
E. \(\frac{8}{7}\)
17 May 2018, 09:16
Kudos
Bookmarks
Bunuel
# of green marbels = 16
# of red marbels = 16
Total # marbels =30
Probability of selecting 1 green marbel = \(\frac{16}{30}=\frac{8}{15}\)... Hence I would go with Option C.
17 May 2018, 09:22
Kudos
Bookmarks
Bunuel
\(\frac{16C_1}{30C_1}\) = \(\frac{16}{30}\) = \(\frac{8}{15}\)
Answer must be (C)
