Bunuel
Let A and B be two regular polygons having a and b sides, respectively. If b = 2a and each interior angle of B is 3/2 times each interior angle of A, then what is the measure of each interior angle, in degrees, of a regular polygon with a + b sides?
A. 100
B. 120
C. 150
D. 160
E. 170
Are You Up For the Challenge: 700 Level QuestionsGiven: Let A and B be two regular polygons having a and b sides, respectively.
Asked: If b = 2a and each interior angle of B is 3/2 times each interior angle of A, then what is the measure of each interior angle, in degrees, of a regular polygon with a + b sides?
Interior angle of a regular polygon \(= \frac{180 (n-2)}{n}\); where n = number of sides of the regular polygon
Interior angle of a regular polygon of sides a \(=180 \frac{(a-2)}{a}\)
Interior angle of a regular polygon of sides b = 2a \(= \frac{180 (2a-2)}{2a} = \frac{180(a-1)}{a}\)
Since {(a-1)/a}{(a-2)/a)} = 3/2
(a-1)/(a-2) = 3/2
a = 4
b = 2a = 8
a+b = 4+8 = 12
Interior angle of a regular polygon of sides (a+b =12)= 180 (12-2)/12 = 150
IMO C