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08 Feb 2022, 04:15
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Let function # be defined as follows: \(\#(x)=\frac{x!+(x+1)!}{(x+2)!}\). What is the value of #(6)?
A. 1/10
B. 1/9
C. 1/8
D. 1/7
E. 1/6
A. 1/10
B. 1/9
C. 1/8
D. 1/7
E. 1/6
sshwetima
Joined: 02 Aug 2019
Last visit: 09 Apr 2023
Posts: 42
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Given Kudos: 165
Location: India
Concentration: Operations, Strategy
Schools: ISB '24 (A)
GMAT 1: 680 Q50 V31
WE:Manufacturing and Production (Manufacturing)
08 Feb 2022, 04:58
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#(x) = x!*[1+(x+1)]/[(x+2)*(x+1)*x!]
#(x) = 1/(x+1)
#(6) = 1/7
Posted from my mobile device
#(x) = 1/(x+1)
#(6) = 1/7
Posted from my mobile device
