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Bunuel
List Q contains 3 elements. What is the median of list Q ?

(1) The mean of list Q is 7.
(2) The mode of list Q is 5.

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(1) The mean of list Q is 7. Let list Q consist of {a,b,c}. This means that a+b+c =21. a,b, and c can be any 3 numbers that add to 21 NS

(2) The mode is 5. Since the mode is 5, the number five must occur at least twice. So, our set Q is either {a,5,5} or {5,5,5}. If Q consists of all 5's then our median is 5. Suppose that we have two 5's in our set. Suppose a <5, for example 4.9. then our set is {4.9,5,5} and our median is 5. Let a >5 such as 5.1. Then our set is |{5,5,5.1} and our median is still 5. Sufficient. Answer is B
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Bunuel
List Q contains 3 elements. What is the median of list Q ?

(1) The mean of list Q is 7.
(2) The mode of list Q is 5.

#1
insufficient
#2
sufficeint ; set can be ( 3,5,5 ) , ( 0,5,5), ( 5,5,8)
median of set can be determined
IMO B
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Also in assymetrical distribution - Median = 1/3(Mode + 2*Mean)

Isn't it?
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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