Vasa056 wrote:
Bunuel what ya think?
Answer is E
Statement 1:
Mean is 7. which means the set could be (0,0,21), (1,10,10). Since there is more than 1 possibility Statement 1 is not sufficient
Statement 2:
Mode is 5. The number 5, in this 3 number set, should be repeated at least twice like (x,5,5) or (5,5,x) or (5,x,5). Statement 2 is not sufficient as well.
In statement 1 your inference that the set might be (0,0,21) is wrong... If you include 0 then the set will have only one element i.e 21... Statement 1 is not sufficient.. the set may be of (7,7,7) or (1,10,10).
In statement 2... (5,x,5) won't hold....
If the mode is 5... Either all the three elements are 5 or atleast 2 of them...If you mean to say that (5,x,5) is the case where X can be either greater than 5 or less than 5. Probably you are wrong...
Take for example X= 8...
You order the elements from smaller to bigger when you find Median.. with that (5,5,8) is possible giving 5 as median...
If X= 3.
Then (3,5,5) will be the case.. . In either of the case you will get median as 5. Statement b is sufficient to answer the question.
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