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Quote:

This is what I found ans by my logic but I'm not sure if it's correct logic or not
average of position no 12 and position no 13. average of 2 absences and 2 absences, = 2 absences= answer
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Can anyone solve this and explain?

This question is discussed in detail here: https://gmatclub.com/forum/the-table-ab ... 69432.html Hope it helps.
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Anyone preparing from Lucknow? Would like to connect for offline preparation and test analysis
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Quote:

Can anyone solve this problem n explain the same
It’s 3 ... correct ?

R should be 9 ... so that makes carry as 1 ... unit digit of (3P + 1) is S and we can see 3P + 1 is greater than 9 as hundred section is having carry over of 1 ... then seeing the options only 13 makes sense ... nothing else which makes 3 is the right option

Please correct if I got wrong
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Quote:

It’s 3 … correct ?
What I noticed first was the unit digit

To get a final unit digit of 4:

5 + R must end in 4

The only possible way is:

5 + 9 = 14

So:

R = 9

and we carry 1 to the tens column.

Now look at the hundreds column:

3 + 4 = 7

But the final hundreds digit is 8, so there must also be a carry of 1 from the tens column.

That means:

P + Q + 1 must create a carry.

Given:

Q = 2P

So:

P + Q = 3P

Now test possible values of P:

If P = 1 → 3P + 1 = 4
If P = 2 → 7
If P = 3 → 10
If P = 4 → 13

We need the tens digit S.

For P = 4:

P + Q + 1 = 4 + 8 + 1 = 13

So the tens digit becomes:

S = 3

Answer: (A)
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P can be 3 and 4 both accordingly S will be 0 and 3 both. Since 0 is not given hence 3 is the only option.

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Hey, Can anyone share GMAT OG 2025-26 study material?
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*WA@moq5356 sends image:*
Question source?

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Hi folks, looking for a serious study partner to keep accountability of each other and discuss study plans. Not really into study marathons etc. Anyone interested?
Pls DM me.
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