M is the sum of three consecutive odd integers, the least of which is

Question

M is the sum of three consecutive odd integers, the least of which is t. In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?

A)  M + 12

B)  M + 6

C)  M - 6

D)  M - 12

E)  \frac{M}{2}

D3N0 · Answer

Ans: D

three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3

Now we need to find t+ t-2+t-4 = 3t -6
=  /3 -6 = M-6-6 = M-12
Ans: D

We can also do this by putting values: 
lets say t = 7 so M= 7+9+11 = 27
 now 7+5+3 = 15 which is 27-12 = so M-12 is the ans.

CounterSniper · Answer

M=t+t+2+t+4
M=3t+6
t=(M-6)/3
M2=t+t-2+t-4
M2=3t-6
M2=3(M-6)/3 -6
M2=M-6-6=M-12

dave13 · Answer

hey there

what did you in highlighted part

thank you

Abhishek009 · Answer

Plug in some numbers and check

Scene I

Let the 3 numbers be 5,7 &9 (Where t = 5)

SO, M = 21

Scene II

Let the 3 numbers be 1 , 3 & 5

SO, M = 9

Now, check ANswer must be 21 - 12 = 9, So, ANswer must be (D)

NandishSS · Answer

HI Bunuel Seems like this question is discussed in the below link

three consecutive odd int of which t is minimum= t, t+2, t+4 so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3 Now we need to find t+ t-2+t-4 = 3t -6 = /3 -6 = M-6-6 = M-12 Ans: D https://gmatclub.com/forum/m-is-the-sum ... fl=similar

Bunuel · Answer

______________________
Fixed. Thank you.

ShubhamDadhe · Answer

I have a doubt regarding the solution to this question:

I understood the below part:

three consecutive odd int of which t is minimum= t, t+2, t+4
so M= t+t+2+t+4 = 3t+6 ; so t= (M-6)/3

Now we need to find t+ t-2+t-4 = 3t -6

But from here on, how did we arrive at the below equation?

= 3(M-6)/2 -6 = M-6-6 = M-12Ans: D

Can somebody please explain this?

bumpbot · Answer

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M is the sum of three consecutive odd integers, the least of which is

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M is the sum of three consecutive odd integers, the least of which is

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

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