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M01-13

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Math Expert
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M01-13  [#permalink]

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New post 16 Sep 2014, 00:15
1
4
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

76% (01:30) correct 24% (01:09) wrong based on 272 sessions

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Math Expert
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Re M01-13  [#permalink]

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New post 16 Sep 2014, 00:15
2
Official Solution:


Because the product of \(x\) and \(y\) is negative, either \(x\) or \(y\) has to be negative.

Statement (1) is not sufficient by itself, because there are many possible combinations of \(x\) and \(y\): -1 and 3, -2 and 4, -3 and 5, etc.

Statement (2) is not sufficient by itself. From Statement (2), we can conclude that \(x\) is either -1 or -2 and \(y\) is positive, but this does not provide enough information to find the value of \(x - y\).

Statements (1) and (2) together are not sufficient. Using both S1 and S2, there are two possible sets:

{\(x=-2\), \(y=4\)} and {\(x=-1\), \(y=3\)}

So the difference can be either 4 or 6.


Answer: E
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Re: M01-13  [#permalink]

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New post 20 Sep 2016, 05:01
Do you mean the difference can be -4 or -6 ?

Since x is negative and y is positive; x-y should be negative.

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Re: M01-13  [#permalink]

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New post 29 Aug 2018, 22:34
Bunuel wrote:
If the product of two integers \(x\) and \(y\) is negative, what is the value of \(x - y\)?


(1) \(x + y = 2\)

(2) \(-3 \lt x \lt y\)


Bunuel

I gave 1 as the ans choice as I thought

x+y=2
-(x-y)=2
x-y=2

Why can't we use this?
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Re: M01-13  [#permalink]

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New post 29 Aug 2018, 22:57
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Re: M01-13   [#permalink] 29 Aug 2018, 22:57
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